How to calculate the percentage of the third year .i want extra detailed steps

The sides of △FGH are FG = 6 x+ 7, GH = 8x - 5, and FH = 10x - 11. If the perimeter of △FGH is 87, list the angles in order from

irga5000 [103]

Answer:

From largest to smallest: FG, FH, GH

Step-by-step explanation:

Given

$FG = 6x + 7$

$GH = 8x - 5$

$FH = 10x - 11$

$Perimeter = 87$

Required

Order the sides in descending order

First, we need to solve for x.

Perimeter of FGH is calculated as thus:

$Perimeter = FG + GH + FH$

Substitute values for FG, GH, FH and Perimeter

$87 = 6x + 7 + 8x - 5 + 10x - 11$

Collect Like Terms

$87 - 7 + 5 + 11= 6x + 8x + 10x$

$96= 24x$

Reorder

$24x = 96$

Divide through by 24

$x = 96/24$

$x = 4$

Substitute 4 for x in FG, GH and FH

$FG = 6x + 7$

$FG = 6 * 4 + 7$

$FG = 24 + 7$

$FG =31$

$GH = 8x - 5$

$GH = 8 * 4 - 5$

$GH = 32 - 5$

$GH = 27$

$FH = 10x - 11$

$FH = 10*4 - 11$

$FH = 40 - 11$

$FH = 29$

In order of arrangement in descending order, we have:

$FG =31$ $FH = 29$ $GH = 27$

4 0

2 years ago

The coordinate plane below represents a city. Points A through F are schools in the city.

Usimov [2.4K]

Part A. The technique on how to find the equation that only applies to point D and E, is to create a line or curve that only includes two of these points. In this case, I created a random parabola that isolates points C and F from the rest of the points. First, we have to find the equation of the parabola through its general forms:

(x - h)² = +/-4a(y-k) or (y - k)² = +/-4a(x - h)

For parabolas drawn like that in the picture, the general form is (x - h)² = +4a(y-k), where the vertex is (h,k) and a is the distance from the vertex to the focus. From the picture, the vertex is at (0,3). Then, we use point D(-2,4) to determine a:

(-2 - 0)² = +4a(4 - 3)
4a = 4

So, the equation of the parabola is:

x² = 4(y - 3)
x² = 4y - 12

Part B. Point D was already verified above. Now for point E(2,4)
x² = 4y - 12
2² ? 4(4) - 12
4 ? 4
4 = 4

Part C. For y < 7x − 4, ignore the equality symbol first and graph the line. Assign random values of x, then you get corresponding values of y. Plot them as shown in the second picture. The line is shown in red. Next, test the equation by choosing a random point. Let's choose the purple point at (4,3).

3 ? 7(4) − 4
3 ? 24
3 < 24

Thus, it applies to the purple point, and all the other areas to that area. The shaded region are all solutions of the inequality. So, Erica is only interested in points E, C and F.

5 0

3 years ago

Find the equation of a straight line passing through the point (0,1) which is perpendicular to the line y=-2x+2

alexandr1967 [171]

Answer:

y = $\frac{1}{2}$ x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 2 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$

The line crosses the y- axis at (0, 1) ⇒ c = 1 , then

y = $\frac{1}{2}$ x + 1 ← equation of perpendicular line

3 0

2 years ago

Three times a number, less twice the number and 9 is 17. What is the number?

Harlamova29_29 [7]

I believe your answer is 8.

Three times a number less than twice the number and nine is seventeen can be written as: 3n - 2n + 9 = 17

Solve for n as follows:

3n - 2n = n

n + 9 = 17

17 - 9 = 8

Hope this helps! :)

7 0

3 years ago

Can someone help me with is and please explain thanks

Andrew [12]

The answer is b because the pattern of these terms r that odd numbers r positive and even numbers are negative. 50 is even so it is negative, while 51 is odd so it is positive. Remember that negative numbers are below zero. If u add something to a negative number it is like subtracting positive numbers. -51+50 is -1. Because if 51 was positive it would be 51 minus 50. The answer is b. If u dont understand or if it is wrong tell me. :D

6 0

2 years ago