to get the slope of it, we simply need two points off the table, say (-4,-114) and (2,48). Recall that the y-intercept, where the graph <u>intercepts</u> the y-axis, when that happens x = 0, so is right there on the table already.

![\bf slope\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{48-(-114)}{2-(-4)}\implies \cfrac{48+114}{2+4}\implies \cfrac{162}{6}\implies 27 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \left(\stackrel{slope}{27}~~,~~\stackrel{y-intercept}{-6} \right)~\hfill](https://tex.z-dn.net/?f=%5Cbf%20slope%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%7B%20y_2-%20y_1%7D%7D%7B%5Cstackrel%7Brun%7D%7B%20x_2-%20x_1%7D%7D%5Cimplies%20%5Ccfrac%7B48-%28-114%29%7D%7B2-%28-4%29%7D%5Cimplies%20%5Ccfrac%7B48%2B114%7D%7B2%2B4%7D%5Cimplies%20%5Ccfrac%7B162%7D%7B6%7D%5Cimplies%2027%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cleft%28%5Cstackrel%7Bslope%7D%7B27%7D~~%2C~~%5Cstackrel%7By-intercept%7D%7B-6%7D%20%5Cright%29~%5Chfill)
0,2 because the y intercept is th middle line so you go up the line and see what number the line goes through
4(2x-4) = 16
4*2x - 4*4 = 16
8x - 16 = 16
8x = 16 + 16
8x = 32 / : 8
x = 4
In general, the scalar multiple of k times u,<span> is this:
</span>
So, here's how we find
The answer is <span><span>(6,12).</span></span>