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ella [17]
3 years ago
13

Find 4+ (-1 2/3). Write your answer in simplest form.

Mathematics
2 answers:
kramer3 years ago
7 0

Answer:

The answer is -5 1/3

Step-by-step explanation:

joja [24]3 years ago
3 0

Answer:

Step-by-step explanation:

-1\frac{2}{3}= -\frac{1*3+2}{3}=-\frac{3+2}{3}=\frac{-5}{3}\\\\\\4+(-1\frac{2}{3})=4 - \frac{5}{3}

                =\frac{4*3}{1*3} - \frac{5}{3}\\\\= \frac{12}{3} - \frac{5}{3}\\\\=\frac{12-5}{3}\\\\=\frac{7}{3}\\\\=2\frac{1}{3}

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Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards
svet-max [94.6K]

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = (\text{Length+width})

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = \sqrt{\text{length}^{2}+\text{width}^{2}}

= \sqrt{(50)^{2}+(120)^{2}}

= \sqrt{2500+14400}

= \sqrt{16900}

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

7 0
3 years ago
A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
HELP!! Simplify the expression 3y^2 • 4x^2y • 5x Using the laws of exponents. Show each step of your work.
JulsSmile [24]
<span>3y^2 • 4x^2y • 5x = (3*4*5) * (</span><span>y^2 * y) * (</span><span>x^2*x) = 60 * y^3 * x^3 = 60 (xy)^3


</span>where ((<span>y^2 * y)) adding the powers in case of multiplication

and also for this:</span><span> (<span>x^2*x)</span>  </span>
5 0
3 years ago
A truck driver drives at a constant rate of 60 miles per hour while on the highway. Which equation represents the distance, d, i
lora16 [44]

Answer:

B

Step-by-step explanation:

this is a rate of time, 60 must be multiplied by the hours to get the days

8 0
3 years ago
Maura writes an expression equivalent to 8a - (-3 - 5a) - 2a. Her work is in the picture. In what step does Maura make a mistake
NISA [10]

Answer:

11a + 3

Step-by-step explanation:

Step 1 : 8a + 3 - 5a - 2a

error => - 5a

8a - (- 3 - 5a) - 2a =

= 8a + 3 + 5a - 2a

= (8a + 5a - 2a) + 3

= 11a + 3

7 0
3 years ago
Read 2 more answers
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