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mel-nik [20]
3 years ago
12

Jacob and Ali want to run from one corner of a football field to the opposite corner. The rectangular football field is 50 yards

wide and 120 yards long. Jacob runs around the perimeter of the field, while Ali runs in a straight line through the middle of the field. How many more yards does Jacob run than Ali?

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

Jacob ran 40 yards more than Ali.

Step-by-step explanation:

Football field is in the shape of a rectangle having dimensions 120 yards × 50 yards

Since Jacob runs around the perimeter of the field from one corner to other corner, therefore, distance run by Jacob = (\text{Length+width})

Distance run by Jacob = 50 + 120 = 170 yards

Ali runs through the middle of the field diagonally on a straight line.

Therefore, distance covered by Ali = \sqrt{\text{length}^{2}+\text{width}^{2}}

= \sqrt{(50)^{2}+(120)^{2}}

= \sqrt{2500+14400}

= \sqrt{16900}

= 130 yards

Now difference between the distance covered by Jacob and Ali

= 170 - 130

= 40 yards

Therefore, Jacob ran 40 yards more than Ali.

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Answer:

Step-by-step explanation:

Eq. 1 )   −5x−3y−9=0

Eq. 2)   4x−18y−54=0

there are two routes to solve this,   Substitution or  elimination,  I'll go for the 2nd one because I can see that the y values are a multiple of each other :)

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Eq. 3) -30x -18y =54

subtract Eq. 2 from Eq. 3  :)

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then:

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now plug that into Eq. 2

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then plug in for either equation

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x = 0

now we have the full answer

check it by plugging in both x and y into the 2nd equation

4(0) - 18(-3) = 54

54= 54

this seems good  

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