Answer:
4
Step-by-step explanation: 5 22 8 18 e
Graph the function and look for sign changes in the slope (easiest)
of the 7 roots 3 are real and 4 are complex
or the perferred way is to apply Descartes rule of signs
x^7-3x^5+4x^2-1=0 a typo in your function attached photos shows 4x²
(x^7) - (3x^5) +(4x^2) - (1) sign changes I see 3
then to find a bound on the number of negative roots
(-x^7) - (-3x^5) +(4x^2) - (1) = -x^7 + 3x^5 + 4x^2 - 1 I see 2 sign changes ??
there is at least 1 real root (due the odd highest power)
and either 0, 2, 4 or 6 complex roots
so 5 and 7 are out
still confused I used a polynomials root calculator
it said ther are three real roots (confirmed by the graph of the function)
and four comple roots (which I can't figure out from the graph)
