Graph. y=–14x+5 MATH
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= 1455
generate a few terms of the sequence using = 3n + 2
= ( 3 × 1) + 2 = 5
= (3 × 2) + 2 = 8
= (3 × 3 ) + 2 = 11
= (3 × 4 ) + 2 = 14
= ( 3 × 5 ) + 2 = 17
the terms are 5, 8, 11, 14, 17
these are the terms of an arithmetic sequence
sum to n terms is calculated using =
[ 2a + (n-1)d]
where a is the first term and d the common difference
d = 8 - 5 = 11 - 8 = 14 - 11 = 3 and = 5
=
[( 2 × 5) + (29 × 3) ]
= 15( 10 + 87) = 15 × 97 = 1455
3,000 is 10 times as much as
3000 = 10 times of what number
We need to find 10 times what number gives us 3000
Let the unknown number be x
3000 = 10 times x
3000 = 10x
To solve for x, we divide by 10 on both sides
300 = x
So, the unknown number is 300
3000 = 10 times 300
3000 is 10 times as much as 300