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max2010maxim [7]
3 years ago
5

if each dimension of a unit cube is increased by 1. what is the ratio between the surface area of the new cube to that of the or

iginal
Mathematics
2 answers:
Fantom [35]3 years ago
6 0
4/1 ^ yea he’s right I remember this
nexus9112 [7]3 years ago
4 0

Answer:

4:1 or 4/1

Step-by-step explanation:

Original surface area: Each side is 1 * 1 = 1 and there are 6 sides, so 1 * 6 = 6.

New surface area: Each side is 2*2 = 4, and there are 6 sides, so 4 * 6 = 24

The ratio would be 24:6, or 4:1. As a fraction, this would be 4/1

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Which geometric figure has the greatest perimeter?
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Step-by-step explanation:

Triangle:

2\sqrt{48}=2\sqrt{2*2*2*2*3}=2*2*2\sqrt{3}=8\sqrt{3}\\\\\\3\sqrt{75}=3*\sqrt{3*5*5}=3*5*\sqrt{3}=15\sqrt{3}\\\\\\6\sqrt{12}=6*\sqrt{2*2*3}=6*2*\sqrt{3}=12\sqrt{3}\\\\\\2\sqrt{108}=2*\sqrt{2*2*3*3*3}=2*2*3*\sqrt{3}=12\sqrt{3}\\\\\\3\sqrt{147}=3*\sqrt{3*7*7}=3*7\sqrt{3}=21\sqrt{3}\\\\Perimeter=3\sqrt{147}+2\sqrt{108}+6\sqrt{12}+2\sqrt{48}+3\sqrt{75}\\\\  =21\sqrt{3}+12\sqrt{3}+12\sqrt{3}+8\sqrt{3}+15\sqrt{3}\\\\=(21+12+12+8+15)\sqrt{3}\\\\=68\sqrt{3}\\

= 68 * 1.732 = 117.78

Square:

\frac{1}{3}\sqrt{63}=\frac{1}{3}\sqrt{3*3*7}=\frac{1}{3}*3*\sqrt{7}=\sqrt{7}\\\\Perimeter=4*side=4*\sqrt{7}=4\sqrt{7} = 4* 2.6458 = 10.58

Rectangle:

\frac{1}{4}\sqrt{100}=\frac{1}{4}\sqrt{10*10}=\frac{1}{4}*10=\frac{5}{2}\\\\\\Perimeter=\frac{1}{4}\sqrt{100}+2\sqrt{48}+4\sqrt{75}+\frac{1}{4}\sqrt{100}+2\sqrt{48}+4\sqrt{75}\\\\=\frac{5}{2}+8\sqrt{3}+20\sqrt{3}+\frac{5}{2}+8\sqrt{3}+20\sqrt{3}\\\\=\frac{5+5}{2}+(8+8+20+20)\sqrt{3}  \\\\=\frac{10}{2}+56\sqrt{3}+\\\\=5+56\sqrt{3}\\\\=5+56*1.732=5+96.99=102

8 0
3 years ago
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