Answer:
The probability that Joe's stock will go up and he will win in the lottery is 0.00005.
Step-by-step explanation:
Let the events be denoted as:
<em>X</em> = the stock goes up
<em>Y</em> = Joe wins the lottery
Given:
P (X) = 0.50
P (Y) = 0.0001
The events of the stock going up is not dependent on the the event of Joe winning the lottery.
So the events <em>X</em> and <em>Y</em> are independent of each other.
Independent events are those events that can occur together at the same time.
The joint probability of two independent events <em>A</em> and <em>B </em>is,
Compute the value of P (<em>X ∩ Y</em>) as follows:
Thus, the probability that Joe's stock will go up and he will win in the lottery is 0.00005.
Derek ran less than 6 miles. If the race is 6 miles, and he only ran 3/8, he ran less than a half of the race. If he didn't finish the race of 6 miles, he couldn't possibly have run 6 miles.
(10x + 4) + (5x-4) ≈ 180
solve for x and you get x≈12
plug 12 in to 5x-4 and you get 56
Answer:
17 cows and 6 geese
Step-by-step explanation:
1. set up two equations:
C + G = 23 (number of cows and geese = total number of animals)
4C + 2G = 80 (cows have 4 legs, geese have 2 legs and the total # of legs is 80)
2. 2(C+G)=2(23) ===> 2C + 2G = 46
3. subtract 4C + 2G = 80 and 2C + 2G = 46 to equal 2C=34, divide by 2 and C=17 (17 cows)
4. apply 17 back to the original (C + G = 23) equation to get: 17 + G = 23, subtract 17 from 23 and G=6 (6 geese)
i hope the way i explained it was clear! :)
