3 years ago

PLEASE PLEASE PLEASE HELP!!!!!! NEED HELP ASAP!!!!

1 answer:

3 0

The answer would be “B”

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slamgirl [31]

Answer:

dhdbdudbdudbdne d ieh eue

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3 years ago

Radda [10]

<h2>Answer with explanation:</h2>

As per given , we have

Sample size : n= 5

Degree pf freedom = : df= 5-1=4

$\mu=\$75.00$

$\sigma=\$13.00$

Significance level for 90% confidence = $\alpha=1-0.90=0.1$

Using t-value table , t-critical value for 90% confidence:

$t_{\alpha/2, df}=t_{0.05, 4}=2.132.$

Margin of error of $\mu$ : $E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\(2.132)\dfrac{13}{\sqrt{5}}=12.3949720129\approx12.39$

Interpretation : The repair cost will be within $12.39 of the real population mean value $\mu$ 90% of the time.

7 0

4 years ago

Ivenika [448]

Really don’t kno it’s a hard question

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3 years ago

VMariaS [17]

$6,435,920,178\\=6,000,000,000+400,000,000+30,000,000+5,000,000\\+900,000+20,000+100+70+8$

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4 years ago

fiasKO [112]

The photo has the answe

6 0

3 years ago