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siniylev [52]
3 years ago
8

A rectangle has a length of √7 meters and a width of (2√5 - √15) meters. What is its area?

Mathematics
2 answers:
Leona [35]3 years ago
8 0
Area of rectangle = Length x Width

√7 x (2√5 - √15)

= 2√35 - √105 m²

Hope it helps!
Jet001 [13]3 years ago
7 0
<h2><u>T</u><u>o</u><u>p</u><u>i</u><u>c</u><u> </u><u>:</u><u>-</u></h2>

Mensuration

<h2><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>:</u><u>-</u></h2>

A rectangle has length of √7 meters and width of ( 2√5 - √15 ) meters.

<h2><u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u></h2>

Area of rectangle.

<h2><u>Formula to be Used :-</u></h2>

\boxed{Area\:of\:rectangle=Length \times Width}

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>:</u><u>-</u></h2>

It is given that,

Length = √7 meters

Width = ( 2√5 - √15 ) meters

<u>A</u><u>p</u><u>p</u><u>l</u><u>y</u><u>i</u><u>n</u><u>g</u><u> </u><u>f</u><u>o</u><u>r</u><u>m</u><u>u</u><u>l</u><u>a</u><u>,</u>

Area = Length × Width

Area = √7 × ( 2√5 - √15 ) sq. meters

Area = ( 2√5 × √7 - √15 × √7 ) sq. meters

Area = ( 2√( 5 × 7 ) - √( 15 × 7 ) ) sq. meters

Area = ( 2√35 - √105 ) sq. meters

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>:</u><u>-</u></h2>

So, area of given rectangle is

( 2√35 - √105 ) sq. meters

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