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3 years ago

10

Please find the Measures of Center and construct a histogram AND find the 5-number summary and construct a box-n-whisker plot fo

r the numbers below.

1 answer:

Hoochie [10]3 years ago

7 0

Step-by-step explanation:

Please find the Measures of Center and construct a histogram AND find the 5-number summary and construct a box-n-whisker plot for the numbers below.

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A box of cereal measures 19.5 cm by 30 cm by 6.5 cm. It is filled to 80% capacity. A cereal bowl is hemispherical and measures 1

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Volume of cereal box=19.5*30*6.5=3802.5cc. The volume of cereal is 80% of this=0.8*3802.5=3042cc.

Volume of the cereal bowl is 2/3(pi)r^3 (half the volume of a sphere 4/3(pi)r^3) where r=radius=12/2=6cm. The volume is therefore 2/3(pi)*216=144(pi)cc.

The number of full cereal bowls is 3042/144(pi)=21.125/(pi)=6.72. So 6 cereal bowls can be filled from the cereal in one cereal box.

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Trials in an experiment with a polygraph include 98 results that include 23 cases of wrong results and 75 cases of correct resul

Evgen [1.6K]

Answer:

$z=\frac{0.765 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-0.866$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of correct cases is not significantly lower than 0.8 or 80%

Step-by-step explanation:

Data given and notation

n=98 represent the random sample taken

X=75 represent the number of correct cases

$\hat p=\frac{75}{98}=0.765$ estimated proportion of correct cases

$p_o=0.8$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.8 or not.:

Null hypothesis: $p \geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.765 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-0.866$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 1% of significance the proportion of correct cases is not significantly lower than 0.8 or 80%

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Answer: 6%

Step-by-step explanation:

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