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Alexxx [7]
2 years ago
6

Two pieces of ribbon, one with a length of 63 inches and another with a length of 42 inches are cut into pieces of equal length

without remainder. Find the greatest possible length that the pieces can be.
Mathematics
2 answers:
alina1380 [7]2 years ago
7 0

Answer:

21

Step-by-step explanation:

the greatest possible length that the two ribbons would be when the ribbons are divided by their lowest common multiple.

The lowest common multiple of 63 is 3. 63/3 = 21

The lowest common multiple of 42 is 2 = 42/2 = 21

damaskus [11]2 years ago
5 0

Answer

224 over 567

Step-by-step explanation:

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How can you use a right angle to decide how to name another angle
blondinia [14]
You can see if the other angles add up to 180 or 360 degrees (depending on shape) then add them to make it the number, for example, if a triangle has a right angle, then the other 2 angles are 45 degrees, knowing that EVERY triangle's angles add up to 180 degrees.
5 0
3 years ago
Use gcf distributive property to find the sum of 28 and 80.
Anna71 [15]

Step-by-step explanation:

The GCF of 28 and 80 is 4.

<u>Distribute 4 for 28 and 80, then solve:</u>

4(7) + 4(20) = 28 + 80

4(7 + 20) = 28 + 80

4(27) = 28 + 80

108 = 80 + 28

7 0
2 years ago
Prime numbers problem :)
Hatshy [7]

Answer:

The answer to your question is (2)(3)(11)

Step-by-step explanation:

Data

154

Process

1.- Find the prime factors of 154, starting with 2, then, 3, 5, 7, etc

                    154  2

                       77  7

                       11   11

                        1

2.- Write 154 as a composition of prime factors

                    154 = (2)(7)(11)

3.- Conclusion

The prime factors of 154 are 2, 3 and 11

7 0
3 years ago
What are the zeros of the function f(x)=x^2-2x-15?
valkas [14]
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
6 0
3 years ago
Read 2 more answers
Point A is the point of concurrency of the angle bisectors of ΔDEF. Point A is the point of concurrency of triangle D E F. Lines
fiasKO [112]

Answer:

  ZA = 3 cm

Step-by-step explanation:

Point A is the incenter of the triangle, so segments AX, AY, and AZ are radii of the circle. They are all the same length, given as 3 cm and confirmed by 3-4-5 right triangle AYD.

  ZA = 3 cm

8 0
3 years ago
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