Answer: D. Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y.
Took the test.
Shift of 6 units right, reflects over x-axis
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Step-by-step explanation:
Given
![x-2y=-16\\Adding\ 2y\ on\ both\ sides\\x=2y-16\\Adding\ 16\ on\ both\ sides\\x+16=2y-16+16\\x+16=2y\\2y=x+16\\Dividing\ both\ sides\ by\ 2\\\frac{2y}{2}=\frac{x+16}{2}\\y=\frac{x}{2}+\frac{16}{2}\\y=\frac{1}{2}x+8\\](https://tex.z-dn.net/?f=x-2y%3D-16%5C%5CAdding%5C%202y%5C%20on%5C%20both%5C%20sides%5C%5Cx%3D2y-16%5C%5CAdding%5C%2016%5C%20on%5C%20both%5C%20sides%5C%5Cx%2B16%3D2y-16%2B16%5C%5Cx%2B16%3D2y%5C%5C2y%3Dx%2B16%5C%5CDividing%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%5Cfrac%7B2y%7D%7B2%7D%3D%5Cfrac%7Bx%2B16%7D%7B2%7D%5C%5Cy%3D%5Cfrac%7Bx%7D%7B2%7D%2B%5Cfrac%7B16%7D%7B2%7D%5C%5Cy%3D%5Cfrac%7B1%7D%7B2%7Dx%2B8%5C%5C)
The equation is in slope-intercept form, the coefficient of x will be the slope of given line. The slope is: 1/2
As the product of slopes of two perpendicular lines is -1.
![\frac{1}{2}*m=-1\\m=-1*\frac{2}{1}\\m=-2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2Am%3D-1%5C%5Cm%3D-1%2A%5Cfrac%7B2%7D%7B1%7D%5C%5Cm%3D-2)
Slope intercept form is:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Putting the value of slope
y=-2x+b
To find the value of b, putting (9,8) in the equation
![8=-2(9)+b\\8=-18+b\\b=8+18\\b=26](https://tex.z-dn.net/?f=8%3D-2%289%29%2Bb%5C%5C8%3D-18%2Bb%5C%5Cb%3D8%2B18%5C%5Cb%3D26)
Putting the values of b and m
![y=-2x+26](https://tex.z-dn.net/?f=y%3D-2x%2B26)
Hence,
The equation of line perpendicular to x-2y=-16 passing through (9,8) is: y=-2x+26
Keywords: Equation of line, Slope-intercept form
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Can you provide a picture ?? or some sort of context