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cricket20 [7]
3 years ago
7

What are the zeros of the function f(x)=x^2-2x-15?

Mathematics
2 answers:
Virty [35]3 years ago
7 0
F(x) = x² - 2x - 15
x = <u>-(-2) +/- √((-2)² - 4(1)(-15))</u>
                        2(1)
x = <u>2 +/- √(4 + 60)</u>
                 2
x = <u>2 +/- √(64)
</u>             2<u>
</u>x = <u>2 +/- 8
</u>           2<u>
</u>x = 1 <u>+</u> 4<u>
</u>x = 1 + 4      x = 1<u /> - 4<u>
</u>x = 5            x = -3<u>
</u>
valkas [14]3 years ago
6 0
To find the zeros of this function, we must first set the entire function equal to 0

f(x) = x² - 2x - 15 = 0

Since this is a quadratic function, we must use the quadratic formula, which is:

\frac{-b +/-  \sqrt{b^{2} - 4(a)(c) } }{2a}

Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15

Now let's plug those in:

\frac{-(-2) +/- \sqrt{(-2)^{2} - 4(1)(-15) } }{2(1)}

which simplifies to:

\frac{2 +/- \sqrt{(4 + 60} }{2}

Simplified further:

\frac{2 +/- \sqrt{(64} }{2}
\frac{2 +/- 8 }{2}
And divide it by the 2 on the bottom gives us:

2 +/- 4

2+4 = 6
2-4 = -2

So the zeros of this function are -2 and 6
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Answer:

Answer: Each pair of opposite sides has the same measure. Therefore, they are congruent. If both pairs of opposite sides of a quadrilateral are congruent, the quadrilateral is a parallelogram.



3 0
3 years ago
Please help asap !! It’s for a exam and it’s due really soon .
harina [27]
-6(3x + 1) I’m sure this is it
3 0
2 years ago
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Which is the graph of y = 1/x?
irina1246 [14]

<u>answer:</u> the first graph

<u>explanation:</u>

it would not be the second one because it is a slope (y = mx + b) and so would be the third choice.

i don't think it would be the last one because it's going only up to 40. which the equation say only y = 1/x and it's not a big number equation.

hope this helps! ❤  from peachimin

i attached this image which is sorta similar to the the to this equation:

6 0
3 years ago
Find the equation of a line that is perpendicular to 4x+6y=1 that has a greater y intercept compared to 2x+3y=18
Marina86 [1]

Answer:

4y = 6x + 40

Step-by-step explanation:

The general equation of a straight line is y = mx + b

m is the slope and b is the y-intercept

let us write both equations in this form;

we have this as;

6y = -4x + 1

y = -4x/6 + 1/6

and;

2x + 3y = 18

3y = -2x + 18

y = -2x/3 + 6

So firstly we want to find an equation that is perpendicular to the first

When two lines are perpendicular, their slopes has a product of -1

The slope of the first line is -4/6

let the slope of the line we want be m

As per they are perpendicular;

-4/6 * m = -1

-4m/6 = -1

-4m = -6

m = 6/4

So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6

we can choose 10

and we have the equation as:

y = 6x/4 + 10

multiply through by 4

4y = 6x + 40

7 0
3 years ago
How do you find this remainder?
makkiz [27]

Answer:

C. 2

Step-by-step explanation:

Look at pic below.

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
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