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3 years ago

Helps me solve this problem please

Mathematics

1 answer:

____ [38]3 years ago

5 0

Step-by-step explanation:

2x + 5y = 6

move it = y= -2x+6

the slope is -2

so, the slope is negative

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Please answer this hurry up thank you so much!

Pepsi [2]

15 liters of water for 40 flower pots

3 0

3 years ago

-2/3- (-3/4) Simplify if needed Brainliest Also, 5/6+5/12

bazaltina [42]

Answer:

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

$\frac{5}{6} + \frac{5}{12} = \frac{5}{3}$

Step-by-step explanation:

Given

$-\frac{2}{3} - (-\frac{3}{4})$

Required

Solve:

$-\frac{2}{3} - (-\frac{3}{4})$

Open bracket

$-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}$

Take LCM

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}$

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

$\frac{5}{6} + \frac{5}{12}$

Take LCM

$\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}$

$\frac{5}{6} + \frac{5}{12} = \frac{15}{12}$

Divide by 3/3

$\frac{5}{6} + \frac{5}{12} = \frac{5}{3}$

4 0

3 years ago

What is the range of the graph shown below

RUDIKE [14]

Theres nothing there tho

8 0

3 years ago

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section

lisabon 2012 [21]

Answer:

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and $y_1(x)=e^{2x}$

To find the $y_2(x)$ we are applying the following formula,

$y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx$

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

$\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx$

$=e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx$

$=e^{2x}\int e^{-4x-4x} \ dx$

$=e^{2x}\int e^{-8x} \ dx$

$=e^{2x}. \frac{e^{-8x}}{-8}$

$=-\frac{e^{-6x}}{8}$

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

4 0

3 years ago

Write an equation of the line perpendicular to

AysviL [449]

Answer:

From general equation of a line:

$y = mx + b$

m » slope, b » y-intercept.

but perpendicularly:

$m _{1} \times m _{2} = - 1 \\ - 3 \times m = - 1 \\ m = \frac{1}{3}$

at point (6, 2):

$2 = ( \frac{1}{3} \times 6) + b \\ 2 = 2 + b \\ b = 0$

therefore, equation is :

${ \boxed{ \boxed{y = \frac{1}{3} x}}}$

8 0

3 years ago