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2 years ago

Helps me solve this problem please

Mathematics

1 answer:

____ [38]2 years ago

5 0

Step-by-step explanation:

2x + 5y = 6

move it = y= -2x+6

the slope is -2

so, the slope is negative

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What is X<br><br> 1+X/2=3x+4 over 9

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X= 2 over 9 or in decimal form 0.2222....

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3 years ago

Which of the fractions below is closest to one?

Ber [7]

Answer:

Step-by-step explanation:

1/4 is 3/4 away from being 4/4 = 1.

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2 years ago

Read 2 more answers

A clogged bathtub drains at a constant rate. The amount of water in the bathtub changes by –3.75 gallons in one hour. What is th

IRINA_888 [86]

Change in the amount of water in the bathtub after -48.75 gallons. Negative sign means water get reduce by 48.75 gallons in bathtub.

<h3><u>Solution:</u></h3>

Given that

A clogged bathtub drains at a constant rate.

The amount of water in the bathtub changes by –3.75 gallons in one hour.

Need to determine change in the amount of water in the bathtub after 13 hour.

Change in amount of water in bathtub in one hour = -3.75 gallons

As given that clogged bathtub drains at a constant rate, so

Change in amount of water in bathtub in 13 hours = 13 x Change in amount of water in bathtub in 1 hours

=> Change in amount of water in bathtub in 13 hours = 13 x ( -3.75 ) = -48.75 gallons

Hence change in the amount of water in the bathtub after -48.75 gallons. Negative sign means water get reduce by 48.75 gallons in bathtub.

4 0

3 years ago

$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e

ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = $p_1$ = $A

And The money invested at 6% = $p_2$ = $13957 - $A

Let The interest earn at 7% = $I_1$

And The interest earn at 6% = $I_2$

$I_1$ - $I_2$ = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, $I_1$ = $\dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}$

Or, $I_1$ = $\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}$

And

$I_2$ = $\dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}$

Or, $I_2$ = $\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}$

∵ $I_1$ - $I_2$ = $833.73

So, $\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}$ - $\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}$ = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = $\dfrac{167115}{13}$

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102 . Answer

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3 years ago

To estimate the mean number of text messages sent by cell-phone users, a researcher chooses a location on a college campus in th

igor_vitrenko [27]

Answer:

the answer is B :)

Step-by-step explanation:

edgen 2020

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3 years ago