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ra1l [238]
3 years ago
15

Tyler is driving home from school and finds that there is road construction being done on his favorite route so he has to take a

detour. Tyler travels 4 km North, 8 km East, 3 Km South, 4 Km West and 6 Km South. What is Tyler's displacement ?
Physics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

<h3>6.4km</h3>

Explanation:

First we must know that the direction along the vertical are towards North and south while along the horizontal are towards east and west.

Sum of distances along the vertical

4km due north = +4km

3 Km South = -3km (south is along the negative y direction)

6 Km South = -6km

total distance along the vertical = 4-3-6 = -5km

Sum of distances along the horizontal;

8km due East = +8km

4 Km west = -4m (west is along the negative x direction)

total distance along the horizontal = 8-4 = 4km

Displacement is gotten by using Pythagoras theorem

d² = x²+y²

d² = (4)²+(-5)²

d² = 16+25

d² = 41

d = √41

d = 6.4km

Hence Tyler's displacement is 6.4km

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Evgen [1.6K]

Answer:

Therefore, the centripetal acceleration of the SUV is <u>3 times</u> ao of the compact car.

Explanation:

FOR SUV:

ac_{suv} = \frac{mv^2}{r}\\

where,

ac_suv = centripetal acceleration of the SUV = ?

m = mass of SUV = 6000 kg

v = speed of SUV = vo

r = radius of path

Therefore,

ac_{suv} = \frac{6000\ vo^2}{r}\\---------------- equation (1)

FOR CAR:

ao = \frac{mv^2}{r}\\

where,

ao = centripetal acceleration of the car = ?

m = mass of car = 2000 kg

v = speed of car = vo

r = radius of path

Therefore,

ao = \frac{2000\ vo^2}{r}\\--------------------- equation (2)

Dividing equation (1) by eq(2):

\frac{ac_{suv}}{ao} = \frac{6000}{2000}\\\\ac_{surv} = 3ao

Therefore, the centripetal acceleration of the SUV is <u>3 times</u> ao of the compact car.

8 0
3 years ago
Which two of the following reduce the background noise in magneto- medicine?
horrorfan [7]

Answer:

The answer is b.) and d.)

Explanation:

The options to reduce the background noise in magneto-medicine are given as follows:

a.) Orienting the heart parallel to the Earth's field

   - This will have no significant effect on the measurements.

b.) Taking the difference of two nearby sensor measurements (gradiometer).

    -This answer is TRUE.

c.) Placing the heart in a perpendicular fashion to the Earth's magnetic field.

   _ This answer also will not have any significant effect on measurements.

d.) Using physical means to shield environmental fields.

   - This answer is TRUE.

4 0
3 years ago
a girl pushes a cart to the left with a 100-N force. A boy pushes it to the right with a 50-N force. what is the net force exert
NNADVOKAT [17]

Answer:

50 to the left

Explanation:

150-100: 50 to the left

3 0
3 years ago
The diver on the diving board is 10 meters high and has a mass of 0.050kg, what is his GPE?
sveta [45]

Answer:

<h2>4.9 J</h2>

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 0.05

We have the final answer as

<h3>4.9 J</h3>

Hope this helps you

6 0
3 years ago
Two resistors, A and B, are connected in series to a 6.0 V battery. A voltmeter connected across resistor A measures a potential
mestny [16]

Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

6 0
3 years ago
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