Answer:
x ≥ 4
Step-by-step explanation:
–4(8 – 3x) ≥ 6x – 8
Distribute
-32 +12x ≥ 6x – 8
Subtract 6x from each side
-32 +12x-6x ≥ 6x-6x – 8
-32 +6x ≥ – 8
Add 32 to each side
-32 +32 +6x≥ 32– 8
6x ≥ 24
Divide by 6
6x/6 ≥ 24/6
x ≥ 4
For the seagull to catch the crab, h(t)=g(t) so:
-16t^2+45=-13t+23 add 16t^2 to both sides
45=16t^2-13t+23 subtract 45 from both sides
16t^2-13t-22=0 using the quadratic equation:
t=(13±√1577)/32, since t>0
t=(13+√1577)/32 seconds
t≈1.65 seconds (to nearest hundredth of a second)
And the height that this occurs using either original equation is:
h((13+√1577)/32)≈1.59 ft (to nearest hundredth of a foot)
The Answer To This Would 1 : 10 Because You Have To Divide Both By 4 So 4 Divided By 4 Gives You 1 And 40 Divided By 4 Gives You 10
~ Hope This Helps :)
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
Answer:
Step-by-step explanation:
15 can go into both 45 and 150 so you divide both into that
45/15 is 3
150/15=10
