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Aleks [24]
3 years ago
11

32^0 is equivalent to _____.​

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

Answer:

1

Step-by-step explanation:

everything to the power of 0 is equivalent to 1 so 32^0 = 1

Sidana [21]3 years ago
5 0

Answer:

1

Step-by-step explanation:

32^0 is equivalent to 1

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The students in Roberto's school are painting a mural that will be 15 feet by 8 feet. First they make a scale drawing of the mur
Verizon [17]

Answer:

x = 2 * (y/5) feets

Step-by-step explanation:

Given that :

Actual dimension of mural = 15 feet by 8 feet

Scale drawing = 2 feet : 5 feet

2 feets on the scale drawing represents 5 feets of the actual drawing.

Drawing length (x)

Actual mural length (y)

x = 2 * (y/5) feets

Hence, dimension of scale drawing:

x = 2 * (15/5) ; x = 2 * (8/5)

x = 6 feets ; 3.2 feets

3 0
3 years ago
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USPshnik [31]
1.6/20 you add everything up and then take the amount of what you’re looking for out
6 0
3 years ago
Solving quadratic equations with complex solutions x2 + 4x + 8 = 0.
Daniel [21]

Answer:

\large\boxed{x=-2\pm2i}

Step-by-step explanation:

x^2+4x+8=0\qquad\text{subtract 8 from both sides}\\\\x^2+4x+8-8=0-8\\\\x^2+2(x)(2)=-8\qquad\text{add}\ 2^2\ \text{to both sides}\\\\x^2+2(x)(2)+2^2=-8+2^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2=-8+4\\\\(x+2)^2=-4\iff x+2=\pm\sqrt{-4}\\\\x+2=\pm\sqrt{(4)(-1)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x+2=\pm\sqrt4\cdot\sqrt{-1}\qquad\text{use}\ \sqrt{-1}=i\\\\x+2=\pm2\cdot i\qquad\text{subtract 2 from both sides}\\\\x=-2\pm2i

4 0
3 years ago
Are these answers correct? If not, what would the answers be?
Ludmilka [50]
Yes you have the correct answers for each of the four problems. Nice work.

For anyone curious,
rd = removable discontinuity
id = infinite discontinuity
c = continuous
7 0
3 years ago
A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,
katovenus [111]

Answer:

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation  

X_{1}=45 represent the number of correct answers for university degree holders

X_{2}=57 represent the number of correct answers for university non-degree holders  

n_{1}=373 sample 1 selected

n_{2}=639 sample 2 selected

p_{1}=\frac{45}{373}=0.121 represent the proportion of correct answers for university degree holders  

p_{2}=\frac{57}{639}=0.0892 represent the proportion of correct answers for university non-degree holders  

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0
3 years ago
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