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Marat540 [252]
2 years ago
13

A ________ is a range of values between which the value of the population parameter is believed to be, along with a probability

that the interval correctly estimates the true population parameter.select one:a. point estimateb. frequentist interferencec. confidence intervald. fiducial inference
Mathematics
2 answers:
Drupady [299]2 years ago
4 0
Question:A ________ is a range of values between which the value of the population parameter is believed to be, along with a probability that the interval correctly estimates the true population parameter
Answer:Confidence intervald
nignag [31]2 years ago
3 0
The best answer out of the ones provided would be c, confidence interval
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2 people working at the same rate will take 6 hours to paint a room.
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Answer:4 hours

Step-by-step explanation:

6*2=12

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Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

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sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

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3 years ago
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sleet_krkn [62]

Answer:

Step-by-step explanation:

7 0
2 years ago
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Elan Coil [88]

Answer:

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Step-by-step explanation:

12x+7<-11

12x<-18

x<-3/2

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x>48/5

Hope this helps!

5 0
2 years ago
Which statement is true?
pishuonlain [190]
D - their slopes are negative reciprocals of each other.
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