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Alik [6]
3 years ago
8

Rationalize the denominator and simplily.​

Mathematics
2 answers:
pychu [463]3 years ago
4 0

Answer:

Step-by-step explanation:

(a-b)² = a²-2ab + b²

(a+b)(a-b)=a²-b²

\frac{\sqrt{a+1} -2}{\sqrt{a+1}+2}= \frac{(\sqrt{a+1}-2)(\sqrt{a+1}-2 )}{(\sqrt{a+1}+2 )(\sqrt{a+1}-2)}\\\\

             =\frac{(\sqrt{a+1}-2 )^{2}}{(\sqrt{a+1} )^{2}-2^{2}}\\\\=\frac{(\sqrt{a+1})^ {2}-2*\sqrt{a+1}*2+2^{2} }{a+1-4}\\\\=\frac{a+1 - 4\sqrt{a+1}+4 }{a-3}\\\\=\frac{a+5-4\sqrt{a+1} }{a-3}

mote1985 [20]3 years ago
3 0

Answer:

( (√ a+ 1) − 2 ) ^2/a-3

Step-by-step explanation:

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a = 4, b= 9. Explanation: Since all of it is to the power of 3, we can divide the exponents to of the results (right side of the equation). 12/3=4, 27/3=9. Hope this helps.
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Feliz [49]

None of the given options are matching. For the expression after putting the value 2 on the place of x. We will get 10 for expression 1 and 0 for the expression 2.

<h3>How can we find the solution to an equation?</h3>

We do same operations on both the sides so that equality of both expressions doesn't get disturbed.

Solving equations generally means finding the values of the variables used in it for which the considered equation is true.

The given equation is;

Equation 1;

\rm 3x+4

Equation 2;

x+6-3x-2

After putting the value 2 on the place of x we get;

Equation 1;

\rm  = 3x+4

=3 \times 2+4 \\ =10

Equation 2;

= x+6-3x-2\\\\\ =2+6-3\times 2-2 \\\\ =2+6-6-2\\\\ =8-6-2 \\\\  = 0

Hence, the none of the given options are matching.

To learn more about the equation, refer to the link;

brainly.com/question/10413253

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Answer:

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Step-by-step explanation:

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