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kap26 [50]
3 years ago
5

The students at underwood high school are building the shape below to put on their school what is the total area of the shape in

square units

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0

Answer:

40

Step-by-step explanation:

area= length times width

1 times 10= 10 times 2= 20

2 times 10=20

20+20=40

You might be interested in
Team D's car went the same distance on each of its trials. Team C's car went exactly 1 cm farther in each trial than Team D's ca
mezya [45]

Answer:

180 cm

Step-by-step explanation:

Number of trials per team = 3

Distance per trial for team D's car is the same for each trial, let distance = x

Distance per trial for team C's car is 1cm farther than team D's distance and the same for each trial, hence, distance = x + 1 per trial

Total distance traveled by C = 543 cm

This means :

(x + 1) + (x + 1) + (x + 1) = 543

3x + 3 = 543

3x = 543 - 3

3x = 540

x = 540 / 3

x = 180

Hence, distance traveled per trial for team D's car = x = 180 cm

8 0
3 years ago
3(3−3)=2(+3)−30 how do I do this???? I'm in 10th grade and this confuses me every time.
astra-53 [7]
Well when you simplify it you get this,

0=-24,


Do what’s inside the parentheses first

3-3 is 0, 3•0 is 0

2•positive 3 is 6

6- -30 is -24

So you have 0=-24

Or just -24 :)
4 0
2 years ago
The Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers ta
Dmitry [639]

Answer:

The answer is below

Step-by-step explanation:

When computing quartile and decile, the data must be arranged in ascending order.

Given the data points:

13 13 13 20 26 26 29 31 34 34 35 35 36 37 38  41 41 41 42 43 46 47 48 49 53 55 56 62 67 82

The numbers are arranged in ascending order. The total number of terms is 30.

a)

First \ quartile(Q_1)=\frac{1}{4}(n+1)^{th}\  term\\\\where\ n=number\ of\ terms. Hence:\\\\Q_1=\frac{1}{4}(30+1)=7.75^{th}\ term=average\ of\ 7th\ and\ 8th\ term=\frac{29+31}{2} =30\\\\Q_1=30\\\\Third \ quartile(Q_3)=\frac{3}{4}(n+1)^{th}\  term\\\\Q_3=\frac{3}{4}(30+1)=23.25^{th}\ term=average\ of\ 23rd\ and\ 24th\ term=\frac{48+49}{2} =48.5\\\\Q_3=48.5

b)

Second \ decile(D_2)=\frac{2}{10}(n+1)^{th}\  term\\\\where\ n=number\ of\ terms. Hence:\\\\D_2=\frac{2}{10}(30+1)=6.2^{th}\ term=average\ of\ 6th\ and\ 7th\ term=\frac{26+29}{2} =27.5\\\\D_2=27.5\\\\\\Eight \ decile(D_8)=\frac{8}{10}(n+1)^{th}\  term=\frac{8}{10}(30+1)=24.8^{th}\ term\\=average\ of\ 24th\ and\ 25th\ term=\frac{49+53}{2} =51\\\\D_8=51

6 0
3 years ago
What is the square root of 6 <br> Sub to my friend plssss
Cerrena [4.2K]

Answer:

The answer to the first question is 2.449489743

Step-by-step explanation:

And I will sub to the channel in a min...

8 0
3 years ago
Which group of ordered pairs are on the line given by the equation 5−2=6
Zolol [24]
Answer: (0,-3)

Explanation: use desmos.con it will help! :)
8 0
3 years ago
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