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Bad White [126]
3 years ago
6

Divide. round your answer to the nearest tenth 26,290.28÷6

Mathematics
1 answer:
Valentin [98]3 years ago
3 0

Answer:

4381.7

Step-by-step explanation:

26290 divided by 6 is 4381.71333333

since 3 is less than 5  and 1 is less than 3 all the nubers get eliminated.

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Write an equation of a line that has a slope of -2 and passes through the point (1,4)
RoseWind [281]

Answer:

y = -2x + 6

Step-by-step explanation:

Since we already have the slope we just need to find the y-intercept.

To do that just plug in the point you were given. (1,4)

4 = -2(1) + b (b represents the y-intercept)

4 = -2 + b (add 2 on both sides)

6 = b

y = -2x + 6 is the equation

Hope this helps!!

3 0
3 years ago
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Does a positive integer times a positive integer equal a positive integer?
hodyreva [135]

Answer:

Yes, two positive real numbers will always equal a positive number. If two numbers have the same sign, whether positive or negative, the product will always be positive.

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3 years ago
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What is the equation of the line that passes through the point (6,3) and has a slope<br> of -1/3?
Vesnalui [34]
The equation is y = -1/3x + 5
6 0
3 years ago
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A rectangle has a length of 28 feet less than 6 times its width. if the area of the rectangle is 98 square feet, find the length
FrozenT [24]

Answer:

w = 18 is the solution

The equation for this problem is 6w - 28 + w = 98

w stands for width

Step-by-step explanation:

7x - 28 = 98 Collect like terms

7w = 98 +28 Move the constant to the right hand side and change its sign

7w = 126 Add the numbers

w = 18 Divide both sides of the equation by 7

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8 0
3 years ago
Its really urgent. I need help with the first question.
RUDIKE [14]
This kind of exercise can be real drudgery.  But it's almost all simple arithmetic, so better you than me.  I'll do one of these for you, which will show you how to do the other one.

a).  sin · cot / sec

You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].

Then the problem becomes

         sin · (cos/sin) / (1/cos)  =  cos²

Aw shucks, I might as well also set up 'b)' for you:

b).  cos · csc / tan

You're supposed to know that [ cosecant = 1/sine ]
and  [ tangent = sine/cosine ].

Then the problem becomes

             cos · (1/sin) / (sin/cos)  =  (cos/sin)²

Now simply plug in the given values of cos A and sin A .


And may I compliment you on your nail care !
7 0
3 years ago
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