B(t)=50×e^2.5t
e^2.5t = 20
t= ln(20) / 2.5
set B(t)=1000 and solve for t via 1000=50e2.5t
20=e2.5t
ln(20)=2.5t
t=ln(20) / 2.5
Answer
Find out the value of x .
To proof
SAS congurence property
In this property two sides and one angle of the two triangles are equal.
in the Δ ADC and ΔBDC
(1) CD = CD (common side of both the triangle)
(2) ∠CDA = ∠ CDB = 90 °
( ∠CDA +∠ CDB = 180 ° (Linear pair)
as given in the diagram
∠CDA = 90°
∠ CDB = 180 ° - 90°
∠ CDB = 90°)
(3) AD = DB (as shown in the diagram)
Δ ADC ≅ ΔBDC
by using the SAS congurence property .
AC = BC
(Corresponding sides of the congurent triangle)
As given
the length of AC is 2x and the length of BC is 3x - 5 .
2x = 3x - 5
3x -2x =5
x = 5
The value of x is 5 .
Hence proved
Answer:
17.2
Step-by-step explanation:
8.7x-1.9x=116.96
6.8x=116.96
x=116.96/6.8
x= 17.2
Answer:
18
Step-by-step explanation:
Multiply 120 and 0.15
Answer:
a. 35 Kilometres.
b. 60 litres.
c. 8150 sweets.
Step-by-step explanation:
<u>Given the following data;</u>
- Distance traveled = 770 km
- Number of days = 22 days
a. To find how many kilometres he traveled in one day;
770 km = 22 days
X km = 1 day
Cross-multiplying, we have;
22X = 770
X = 770/22
<em>X = 35 Kilometres.</em>
b. To find how many litres he would need to go 840 km;
1 litre = 14 kilometres
X litres = 840
Cross-multiplying, we have;
14X = 840
X = 840/14
<em>X = 60 litres.</em>
c. To find how many sweets are there in his car;
Number of sweet box, Ns = 326 boxes
Number of sweets in each box, Sw = 25 sweets
Total number of sweets = Ns * Sw
Total number of sweets = 326 * 25
<em>Total number of sweets = 8150 sweets.</em>
