Answer: the lower left data set matches the line plot, or the one with the most values
LxW 5x5=25 If you know one side is five than the other side is 52 because they’re both equal its the radius compared to the diameter radius is five the diameter is 10
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Answer:
530.087 trust me
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let y be the total charge and x no of hours spent for cutting the lawn,
Then for Allan we have the equation as
y = 8.50x+15
SInce 15 is the fixed charge and 8.50 is charged per hour we get the above equation for Allan.
Next similarly for Taylor, we have fixed charges 12 and variale 9.25
y =9.25x+12
When Taylor total charges is greater than Allan's total charge
we have 9.25x+12>8.5x+15
Simplify to get
0.75x>3
Or x>4
Whenever x i.e. no of hours exceed 4, Taylor charges will be greater than that of Allan