Answer:
This proves that f is continous at x=5.
Step-by-step explanation:
Taking f(x) = 3x-1 and 
, we want to find a 
such that 
At first, we will assume that this delta exists and we will try to figure out its value.
Suppose that 
. Then
.
Then, if , then 
. So, in this case, if 
we get that . The maximum value of delta is 
.
By definition, this procedure proves that 
. Note that f(5)=14, so this proves that f is continous at x=5.
The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is
... C (2x+1)(3x+5)
_____
If you multiply that out, you get 6x² + 10x + 3x + 5 = 6x² +13x +5, as required.
The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.
When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.
Step-by-step explanation:
(x+10)(x-0)=0
x=-10 and x=0
(-10)^2+10(-10)+h=h
100-100+h=h
0=0
0^2+10(0)+h=h
0+h=h
0=0
I think,you miss some numbers
if you don't miss some numbers, this solution is no solution
Answer:
photomath, assistant in mathematics, will decompose everything and give the correct answer.
Find the probability of rolling a number bigger than 4 and subtract that by 100%;
P(5)= 1/6 <-- 6 possible outcomes, 1, 2, 3, 4, 5 or 6
P(6)= 1/6
You could have rolled a 5 or 6. When the word or is used, the probabilities are added together, when and is used, they are multiplied.
(1/6)+(1/6)=2/6
1-P(5)+P(6)
=1-(2/6)
=(6/6)-(2/6)
=4/6
Therefore the probability of not rolling a number larger than 4 is 4/6 or 2/3.
Hope I helped :)
