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kiruha [24]
2 years ago
12

If Oliver actually worked a total of fourteen hours doing his 14 shifts at Slow Food to Go, how many hours was he scheduled to w

ork each shift
Mathematics
1 answer:
fiasKO [112]2 years ago
7 0

Answer:

His shifts were 1 hour each

Step-by-step explanation:

If Oliver worked a total of 14 hours in a span of 14 shifts, that would mean he worked 1 hour per shift because 1(14) = 14.

14/14 = 1 hour

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Umnica [9.8K]

Answer:

Answer is 15-r .Hope it will help you

6 0
2 years ago
Consider the differential equation x^2 y''-xy'-3y=0. If y1=x3 is one solution use redution of order formula to find a second lin
Anastasy [175]

Suppose y_2(x)=y_1(x)v(x) is another solution. Then

\begin{cases}y_2=vx^3\\{y_2}'=v'x^3+3vx^2//{y_2}''=v''x^3+6v'x^2+6vx\end{cases}

Substituting these derivatives into the ODE gives

x^2(v''x^3+6v'x^2+6vx)-x(v'x^3+3vx^2)-3vx^3=0

x^5v''+5x^4v'=0

Let u(x)=v'(x), so that

\begin{cases}u=v'\\u'=v''\end{cases}

Then the ODE becomes

x^5u'+5x^4u=0

and we can condense the left hand side as a derivative of a product,

\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0

Integrate both sides with respect to x:

\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C

x^5u=C\implies u=Cx^{-5}

Solve for v:

v'=Cx^{-5}\implies v=-\dfrac{C_1}4x^{-4}+C_2

Solve for y_2:

\dfrac{y_2}{x^3}=-\dfrac{C_1}4x^{-4}+C_2\implies y_2=C_2x^3-\dfrac{C_1}{4x}

So another linearly independent solution is y_2=\dfrac1x.

3 0
3 years ago
Sixty percent of students in Mariana's class has a pet. If 12 students have pets, how many students are in the class
Likurg_2 [28]
20 students, because 12 is 60% of 20.
6 0
3 years ago
Need help ASAP !!!!!!!!!!!
Lana71 [14]

i think the answer b or c

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5 0
3 years ago
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Assoli18 [71]

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1.4 = 4 + 9((rm^-4)

1.4 = 9rm ^-32

33.4 = 9rm

Rm = 3.71

The answer is 3.71

3 0
2 years ago
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