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4 years ago

Which of these is the algebraic expression for some number to the power five

Mathematics

2 answers:

Studentka2010 [4]4 years ago

8 0

It would be x^5. Bc x is raised to to the fifth power

DochEvi [55]4 years ago

6 0

Answer:

x^5

Step-by-step explanation:

x raised to the power 5 is written as

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Given the graph of the function f below, estimate the intervals in which fis increasing.

nadezda [96]

Answer:

(-∞, -5/2) ∪ (1, ∞)

Step-by-step explanation:

"Increasing" means the graph goes up to the right. It is increasing from the left up to the local maximum--the peak at left.

It is increasing again from the local minimum on the right to the right side of the graph.

The two sections where the graph is increasing are ...

(-∞, -5/2) ∪ (1, ∞)

The graph is decreasing between the maximum on the left and the minimum on the right.

6 0

3 years ago

Mara's family is driving to her grandmothers' house. The family travels 239.4 miles between the hours of 9:10 a.M. To 1:40 p.M.

anzhelika [568]

Answer:

53.2 mph

Step-by-step explanation:

Mara's family travels 239.4 miles between the hours of 9:10 a.m. to 1:40 p.m.

1:40 p.m. is 13:40.

Thus, they traveled for

13 hours 40 minutes - 9 hours 10 minutes = 4 hours 30 minutes

that is $4\frac{1}{2}=4.5$ hours.

Use formula:

$D=r\cdot t,$

where

D = distance

r = rate

t = time.

In your case,

D = 239.4 miles

t = 4.5 hours

Hence,

$239.4=4.5r\\ \\r=\dfrac{239.4}{4.5}=53.2\ mph$

5 0

3 years ago

Read 2 more answers

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at t time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago

An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 4 ft long with a diameter of 2.2 ft. S

gavmur [86]

Answer:

$8\:\mathrm{minutes}$

Step-by-step explanation:

The volume of a cylinder is given as:

$r^2\cdot\pi\cdot h$

Since the diameter is $2.2$ , the radius is $\frac{2.2}{2}=1.1$ .

Therefore, the volume of this cylinder is:

$1.1^2\cdot 3.14\cdot 4=15.1976\:\mathrm{ft^3}$ , using $\pi=3.14$ as requested in the problem.

Since the tank is emptied at a constant rate of $1.5\:\mathrm{ft^3\:per\:minute}$ , it will take

$\frac{15.1976}{1.5}=7.5988=\fbox{$8\:\mathrm{minutes}$}$ to empty the tank.

8 0

3 years ago

The solutions of x2=169

tresset_1 [31]

Answer:

x=13

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers