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2 years ago

Estimate 307% of 29.

Mathematics

1 answer:

aleksley [76]2 years ago

6 0

Answer:

89.03

Step-by-step explanation:

29x3.07=89.03

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When a number x is multiplied by 9, the result is 35 . What is the value of x?

svp [43]

a number x is multiplied by 9 : 9x

a number x is multiplied by 9, the result is 35 : 9x = 35

solve for x

9x = 35
x = 35/9
x = 3 8/9 (3 and 8/9)

4 0

3 years ago

At the hairdresser, Jenny had 27 centimeters cut off her hair. How many decimeter of hair did Jenny have cut off

Serhud [2]

1 decimeter is 10 centimeter so you divide 27 by 10 and get 2.7
So she cut 2.7 decimeter off her hair

4 0

3 years ago

Write the recurring decimal 0.4 as a fraction in its simplest form.

Ugo [173]

Answer:

2/5

Step-by-step explanation:

0.4 = 4/10 which in simplest form is 2/5

8 0

2 years ago

Read 2 more answers

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

2 years ago

No links, will be reported

kirza4 [7]

Answer:

(1,0)

Step-by-step explanation:

This is because a system of equations is when two lines cross to form a point that they share. (1,0) is the point where the two lines cross/intersect.

6 0

1 year ago

Read 2 more answers