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2 years ago

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A truck has left Amsterdam with a speed of 52 mph. After 5 hours a car has left Amsterdam with a speed of 78 mph. At what distan

ce from Amsterdam will the car catch up with the truck?

2 answers:

torisob [31]2 years ago

7 0

It would be 10 hours but the distance would be 260 mph.

Zina [86]2 years ago

7 0

Answer:

780 miles

Step-by-step explanation:

Before the car started its journey, the truck was already 260 miles ahead of the car.

52 miles per hour for 5 hours is $52*5=260$ miles

From then onwards, the car travels at 78mph and truck still 52mph. How much faster is the car?

$78-52=26$ miles per hour

<em><u>This means the car is catching up on the truck at 26 miles every hour! </u></em>

And we know the distance to catch up is 260 miles.

<em>So at 26 miles every hour, how long would it take the car to catch up 260 miles?</em>

$\frac{260}{26}=10$ hours.

We want to know how far are they from Amsterdam when the catch up happens. So in 10 hours at 78 miles per hour, the car is $78*10=780$ miles from Amsterdam <em>(this is when catch up occurs).</em>

So the distance is 780 miles from Amsterdam

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

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b

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c

The correct option is D

Step-by-step explanation:

From the question we are told that

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The largest value is k = 15

The smallest value is u = 7

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Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

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Here the Range is mathematically represented as

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=> $Range = 15 - 7$

=> $Range = 8$

=> $\sigma = \frac{8 }{4}$

=> $\sigma = 2$

Generally the sample size is mathematically represented as

$n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ] ^2$

=> $n = [1.96 * 2 }{0.23} ] ^2$

=> $n =290$

Generally to obtain a conservatively small sample size the population standard deviation estimate becomes

=> $\sigma = \frac{Range }{6}$

=> $\sigma = \frac{8 }{6}$

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Generally the conservatively small sample size is mathematically evaluated as

$n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ] ^2$

=> $n = [1.96 * 1.333 }{0.23} ] ^2$

=> $n =129$

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2 years ago

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evablogger [386]

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$w=\frac{a}{t}\\ \\a=wt\\\\a=(4)(\frac{5}{12} )\\\\a=\frac{5}{3}$

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2 years ago