Answer:
D
Step-by-step explanation:
So we have the expression:
And we want to evaluate it when x=25, y=10, w=11, and z=18.
So, substitute these values for the variables:
First, subtract within the parentheses:
Square 15:
Now, multiply the terms on the right. 10 times 11 is 110:
Multiply:
Finally, add:
So, our answer is D.
And we're done!
Order of Operations = PEMDAS
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Yes because
Kate: 3X2 = 6
Jake: 3X2 = 6
Emily: 3X2 = 6
add all of those together and you get 18
<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
The perimeter of the a and BC is 14 unitsBecause if you add all of the sides together you get 14 and I need points
