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2 years ago

Find the value of the numerical expression. 43 x 41 x 42

Mathematics

1 answer:

saw5 [17]2 years ago

6 0

Answer:

74046 is the correct answer

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A computer company produces an extremely light laptop and they claim it is the lightest on the market weighing only 32 ounces. t

Darina [25.2K]

Solution: We are given:

$\mu=0.33, \sigma =0.7$

Let $x$ be the weight (oz) of laptop

We have to find $P(x>32)$

To find the this probability, we need to find the z score value.

The z score is given below:

$z=\frac{x-\mu}{\sigma}$

$=\frac{32-33}{0.7}$

$=-1.43$

Now, we have to find $P(z>-1.43)$

Using the standard normal table, we have:

$P(z>-1.43)=0.9236$

0.9236 or 92.36% of laptops are overweight

4 0

3 years ago

£1800 is invested at4% compound interest per year.

deff fn [24]

2000=1800(1.04)^t,,log(1.11)/log(1.04)=t use the calculator,,,hope it helps :-)

3 0

3 years ago

Use the function below to find F(4)

Ne4ueva [31]

Answer:

A 256/3

Step-by-step explanation:

1/3 * 4^4 =

1/3 * (4*4*4*4) =

1/3 * 256 = 256/3

4 0

2 years ago

Read 2 more answers

5 + (-2) Is it negative or positive

densk [106]

Answer:

its positive

Step-by-step explanation:

5 + (-2) = 3

8 0

3 years ago

Read 2 more answers

Suppose the object moving is Dave, who hasamassofmo =66kgatrest. Whatis Daveâs mass at 90% of the speed of light? At 99% of the

nignag [31]

Step-by-step explanation:

Formula that relates the mass of an object at rest and its mass when it is moving at a speed v:

$m=\frac{m_o}{\sqrt{1-\frac{v^2}{c^2}}}$

Where :

m = mass of the oebjct in motion

$m_o$ = mass of the object when at rest

v = velocity of a moving object

c = speed of the light = $3\times 0^8 m/s$

We have :

1) Mass of the Dave = $m_o=66 kg$

Velocity of Dave ,v= 90% of speed of light = 0.90c

Mass of the Dave when moving at 90% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.90c)^2}{c^2}}}$

m = 151.41 kg

Mass of Dave when when moving at 90% of the speed of light is 151.41 kg.

2) Velocity of Dave ,v= 99% of speed of light = 0.99c

Mass of the Dave when moving at 99% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.99c)^2}{c^2}}}$

m = 467.86 kg

Mass of Dave when when moving at 99% of the speed of light is 467.86 kg.

3) Velocity of Dave ,v= 99.9% of speed of light = 0.999c

Mass of the Dave when moving at 99.9% of the speed of light:

$m=\frac{66 kg}{\sqrt{1-\frac{(0.999c)^2}{c^2}}}$

m = 1,467.17 kg

Mass of Dave when when moving at 99.9% of the speed of light is 1,467.17 kg.

4) Mass of the Dave = $m_o=66 kg$

Velocity of Dave,v=?

Mass of the Dave when moving at v speed of light: 500

$500 kg=\frac{66 kg}{\sqrt{1-\frac{(v)^2}{(3\times 10^8 m/s)^2}}}$

$v=2.973\times 10^8 m/s$

Dave should be moving at speed of $2.973\times 10^8 m/s$ .

4 0

3 years ago