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2 answers:
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Given:
John invest $5,000 in one account and $8,000 in an account paying 4% more in interest.
Total interest in one year = $1230
To find:
The rates of the investments.
Solution:
Let x% be the rate of interest on investment $5000.
Then, (x+4)% is the rate of interest on investment $8000.
Total interest is $1230. So,
Divide both sides by 130.
Now,
Therefore, $5,000 is invested at 7% and $8,000 is invested at 11%.
Answer:
Option A
Step-by-step explanation:
From the graph given in the picture,
Function 1
Rate of change = Slope of the line
Slope of a line passing through two points and
is,
Slope =
Therefore, slope of the given line which is passing through (1, 2) and (-1, -2)will be,
Rate of change = = 2
Function 2
Equation of the line is,
y =
By comparing this equation with slope-intercept form of the equation,
y = mx + b
Here m = rate of change Or slope of the linear function
Rate of change of function 2 =
Therefore, rate of change of function 1 is higher than function 2.
Option A will be the answer.