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Mnenie [13.5K]
3 years ago
11

There are 4 roads leading from Bluffton to​ Hardeeville, 6 roads leading from Hardeeville to​ Savannah, and 5 roads leading from

Savannah to Macon. How many ways are there to get from Bluffton to​ Macon?
Mathematics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

120 ways.

Step-by-step explanation:

From the given information:

Total number of roads leading from Bluffton to​ Hardeeville = 4

Total number of roads leading from Hardeeville to​ Savannah = 6

Total number of roads leading from Savannah to Macon = 5

We need to find the total number of ways to get from Bluffton to​ Macon.

Total number of ways to get from Bluffton to​ Macon = 4\times 6\times 5= 120

Therefore, there are 120 required number of ways to get from Bluffton to​ Macon.

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Part A.) A garden hose supplies 36 gallons of water in 3 minutes. Use a table of equivalent ratios to show the garden house's wa
saw5 [17]

Answer: It would be 360 gallons of water per 10 mins because

Step-by-step explanation:

You multiply 36×10 and you get 360 gallons

7 0
3 years ago
A gardener planted some seedlings at equal distances apart along a straight road. The 3rd seedling and the 5th seedling were 9/1
ratelena [41]

Answer:

Answer:

17 seedlings

Step-by-step explanation:

Given;

The seedlings are at an equal distance in a straight line.

Distance between 3rd seedling and 5th seedling = 9/10 m

So, distance between 3rd seedling and 4th seedling = 9/10 ÷ 2 = 9/20 m

So, the distance between two seedlings in a line = 9/20 m

The given distance between 2nd seedling and the last seedling = 6 3/4 m = 27/4 m

8 0
2 years ago
Expand the number 1120 into its corresponding exponential form. 25 · 5 · 7 52 · 8 22 · 53 · 7 2 · 5 · 7
Eduardwww [97]

Answer:

(A) 2^{5} * 5 * 7

Step-by-step explanation:

Your question formatting made it very complicated to understand the possible answers.  Please use some notation or the equation editor next time.

So, the exponential form a way to write a number using multiplications and powers.

Let's examine the various options (if I read them correctly)

(A) 2^{5} * 5 * 7 - YES!

2^{5} is 32, so 32 * 5 * 7 = 160 * 7 = 1120

(B) 5² · 8  - NO

= 25 * 8 = 200

(C) 2² * 5³ * 7 - NO

= 4 * 125 * 7 =500 * 7 = 3500

(D) 2 · 5 · 7 - NO

= 10 * 7 = 70

5 0
3 years ago
Find the greatest common factor 32a^3b^2, 44ab^3 and 40a^2b
Ronch [10]
\32a^3b^2 \ , \  44ab^3 \ , \  40a^2b\\


\text {Taking out common factor : } \\ \\
4ab(8a^2b) + 4ab(11b^2) + 4ab(10a)

\text { greatest common factor =  } 4ab
3 0
3 years ago
PLEASEHELP!
denis-greek [22]
You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5

100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10

6 0
3 years ago
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