Area of a parallelogram = A =base*height
so in this case is just (1½)(6).
first off let's convert the mixed fraction to "improper",
Answer:
oof
Step-by-step explanation:
Answer:
17. 6
18. 18 (as shown)
19. 10/3 = 3 1/3
20. 20/3 = 6 2/3
Step-by-step explanation:
17. For this, you can subtract the given length GB=12 from the length you found for problem 18, BF=18. Doing that tells you FG = 18-12 = 6, as you have marked on the diagram.
19. As with median BF, the point G divides it into two parts that have the ratio 1:2. The distance from G to D is the shorter of the distances, so you have ...
... GD = (1/3) CD = (1/3)·10 = 10/3
... GD = 3 1/3
20. You can subtract GD from CD to get CG, or you can multiply CD by 2/3. The result is the same either way.
... CG = CD -GD = 10 -3 1/3
... CG = 6 2/3
_____
<em>Comment on centroid and median</em>
The centroid (G) divides each median into parts in the ratio 1:2. Hence the shorter of those parts is half the length of the longer one, or 1/3 the total length of the median.
The longer of the parts is double the length of the shorter one, or 2/3 the total length of the median.
Your marking of median BF seems to show an understanding of these relationships. (Total length: 18; length of parts: 6 and 12.)
Answer:
0.216
Step-by-step explanation:
Given that a certain new type of business succeeds 60% of the time.
3 such businesses are tested for success.
Since these three businesses open (where they do not compete with each other, so it is reasonable to believe that their relative successes would be independent). we can say X no of successful businesses is Binomial
with p = 0.6 and n =3
Required probability
=The probability that all 3 businesses succeed is:
= 
Answer:
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Step-by-step explanation:
The constraints on protein, minerals, and vitamins give rise to the inequalities ...
40c +30k ≥ 150 . . . . . . required protein
20c +20k ≥ 90 . . . . . . required minerals
10c +30k ≥ 60 . . . . . . . required vitamins
And we want to minimize 10c +12k.
The graph shows the vertices of the feasible region in (c, k) coordinates. The one that minimizes cost is (c, k) = (3.75, 0.75).
To minimize cost, the daily feed should be ...
- 3.75 bags of ChowChow
- 0.75 bags of Kibble
Daily cost will be $46.50.