Answer: 73 weeks
Step-by-step explanation:
Equations
657-4w=876-7w
Solve for w
w=73
Answer:
8,9,11
Step-by-step explanation:
A-1
B-2
C-3
D-4
E-5
F-6
G-7
H-8
I-9
J-10
K-11
L-12
M-13
N-14
O-15
Answer:
(a) 
(b) Domain:
<em>(See attachment for graph)</em>
(c) 
Step-by-step explanation:
Given



Solving (a): A function; l in terms of w
All we need to do is make l the subject in 
Divide through by 2

Subtract w from both sides


Reorder

Solving (b): The graph
In (a), we have:

Since l and w are the dimensions of the fence, they can't be less than 1
So, the domain of the function can be 
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To check this
When 



When 


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<em>See attachment for graph</em>
<em></em>
Solving (c): Write l as a function 
In (a), we have:

Writing l as a function, we have:

Substitute
for l in 
becomes

Answer:
Step-by-step explanation:
4/9-1/6=5/18
Answer:

Step-by-step explanation:
The given equation is 
Group similar terms to get:


Square both sides to obtain:


Add 6 to both sides

Simplify the right hand side to obtain;
