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Varvara68 [4.7K]
3 years ago
7

The flower shop sold roses and tulips. The number of roses sold was 5 less than twice the number of tulips sold. If the shop sol

d 106 flowers in total, how many of each kind of flowers were sold?
Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0

Answer: the number of roses sold is 69 while number of tulips is 37

Step-by-step explanation:

Let x represent the number of roses that the flower shop sold.

Let y represent the number of tulips that the flower shop sold.

The number of roses sold was 5 less than twice the number of tulips sold. This means that

x = 2y - 5 - - -- -- - - - - - ;1

If the shop sold 106 flowers in total, it means that

x + y = 106

Substituting x = 106 - y into equation 1, it becomes

106 - y = 2y - 5

3y = 106 + 5 = 111

y = 111/3 = 37

x = 106 - y = 106 - 37

x = 69

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Eight people are equally sharing 12 muffins. How many muffins will each person receive?
Marina CMI [18]
Total number of muffins = 12 muffins
Total number of people sharing muffin = 8

Muffins each person will receive = Total number of muffins
                                                          ---------------------------------
                                                          People sharing muffins
                                                   
                                                    = 12/8
                                                    = 1 1/2  OR  1.5 muffins



7 0
3 years ago
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The vertices of a triangle are A(7,5) B(4,2) and C(9,2) what is mABC
shutvik [7]

Answer:

A(7,5)

Step-by-step explanation:

This is correct because the area of a triangle is b × h = a.

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3 years ago
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Solve the system.
goldenfox [79]
The answer is b, infinite solutions
4 0
3 years ago
How would you solve a problem like this
RUDIKE [14]

Answer:

ΔGJH ≅ ΔEKF

HL: GH and EF

SAS: FK and JH (or GH and EF)

ASA: ∠JGH and ∠FEK (or ∠EFK and ∠JHG)

ΔGFJ ≅ ΔEKH

SSS: KH and FJ

SAS: ∠KEH and ∠FGJ

Step-by-step explanation:

List whatever angles/sides need to be congruent for the two triangles to be congruent.

Prove ΔGJH ≅ ΔEKF using....

- HL (Hypotenuse + Leg)

           We already have two legs that are congruent (EK and GJ), so we just need the hypotenuses (GH and EF) to be equal.

- SAS (Side + Angle + Side)

         1 pair of sides (EK and JG) are equal, and m∠EKF = m∠GJH. So we need one more side. You can either use FK and JH or GH and EF.

- ASA (Angle + Side + Angle)

         1 pair of angles (∠EKF and ∠GJH) are already given as equal, and 1 pair of sides (EK and GJ) are equal. We just need one more pair of angles. So either ∠JGH and ∠FEK or ∠EFK and ∠JHG.

Prove ΔGFJ ≅ ΔEKH using...

- SSS (Side + Side + Side)

          Two pairs of sides (EK + GJ and EH + FG) are equal, so KH and FJ need to be equal.

- SAS (Side + Angle + Side)

          FG + EH and KE + GJ are equal. We need to use the angle in between them to use SAS, so ∠KEH and ∠FGJ need to be equal.

7 0
3 years ago
Find the length of each side of the polygon for the given perimeter.
Zepler [3.9K]

As the picture highlights, the opposite sides have the same lengths. The perimeter is the sum of all lengths, so we have

P = 2(2s-5) + 2(4s-13)

Plug the required value for the perimeter and expand the right hand side:

108 = 4s-10 + 8s-26

Simplify the right hand side:

108 = 12s-36

Add 36 to both sides:

144 = 12s

Divide both sides by 12:

12 = s

Now that we know the value for s, let's deduce the lengths of the sides:

2s-5 = 2\cdot 12 - 5 = 24-5 = 19

4s-13 = 4\cdot 12 - 13 = 48-13 = 35

3 0
3 years ago
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