The graph has a vertex at (3, -2). It extends upward from there linearly at a slope of -1 to the left and 1 to the right. It is the graph of an absolute value function. If we assume it keeps extending upwards the domain is all real numbers. (which is what i would assume even though there's no arrows it doesn't have decipherable endpoints). The range is y ≥ -2 with y -intercept (0,1), and x-intercepts: (5,0) & (1,0).
To write the equation for this function, I would acknowledge that it is the translation of the graph of the standard absolute value function: f(x) = |x| ; right 3 and down 2. Which would be to subtract 3 from x and subtract 2 from the end.
f(x) = |x - 3| - 2
The first step is to write each factor in expanding notation.
This is:
- 124 = 100 + 20 + 4
- 2 = 2
Now muliply 2 times each term of the terms 100, 20 and 4
=> 2 * 100 = 200
2 * 20 = 40
2 * 4 = 8
Then,
(100 + 20 + 4 )
x 2
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8
40
200
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248
Using the Empirical Rule, it is found that:
- a) Approximately 99.7% of the amounts are between $35.26 and $51.88.
- b) Approximately 95% of the amounts are between $38.03 and $49.11.
- c) Approximately 68% of the amounts fall between $40.73 and $46.27.
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The Empirical Rule states that, in a <em>bell-shaped </em>distribution:
- Approximately 68% of the measures are within 1 standard deviation of the mean.
- Approximately 95% of the measures are within 2 standard deviations of the mean.
- Approximately 99.7% of the measures are within 3 standard deviations of the mean.
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Item a:
Within <em>3 standard deviations of the mean</em>, thus, approximately 99.7%.
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Item b:
Within 2<em> standard deviations of the mean</em>, thus, approximately 95%.
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Item c:
- 68% is within 1 standard deviation of the mean, so:
Approximately 68% of the amounts fall between $40.73 and $46.27.
A similar problem is given at brainly.com/question/15967965
Answer:
length 11 width 4
Step-by-step explanation:
perimeter:
11+11=22
4+4=8
22+8=30
area:
11*4=44
(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0 ............ let z = 3^x
(z - 3)(z + 1) = 0
If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x
If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is
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Answer: x = 1
