Line 1 has slope of 1 and y-intercept at 4 line 1 equation in y = mx + b form: y = x + 4
line 2 has slope of -1/2 and y-intercept of 1 you can calculate this using slope formula or count rise/run to get to next point: like line 2 has points (-2, 2) and (0,1)
so slope = (1 - 2)/(0 - (-2) ) = -1/2
line 2 has y=mx+b form of y = -1/2x + 1
try to convert all the systems into y=mx+b form and see if they get our equations for lines 1 and 2:
line 1: y = x + 4 line 2: y = -1/2x + 1
for system F
4x + 2y = -18 2x - 2y = 9
if we try changing 4x + 2y = -18 to isolate y:
4x + 2y = -18 2y = -4x - 18 y = -4/2x - 18/2 y = -2x - 9
this choice is wrong since none of our slopes are 2
try system G: 2x + 4y = 6 -2x + 2y = 4
if we try changing 2x + 4y = 6 to isolate y
2x + 4y = 6 4y = -2x + 6 y = -2/4x + 6/4 y = -1/2x + 3/2
the graphs don't have y-intercept at 3/2 so this is wrong
try system H: 2x + 4y = 4 -2x + 2y = 8
if we try converting 2x + 4y = 4 we get
2x + 4y = 4 4y = -2x + 4 y = -2/4 x + 4/4 y = -1/2x + 1
This matches with line 2: y = -1/2x + 1 so try converting the other equation in this system to see if this is the right answer
