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Margaret [11]
3 years ago
13

For any real number b, b2=

Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

Taking the square root of the square of a Real Number would give you the Real Number

Answer

OPTION D

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3. In a certain school, there are 456 girls. Calculate the total number of students
marin [14]

Answer:

3) girls = 24% = 456

let the total number of students be = x

\frac{24}{100}  \times x = 456

x = 456 \times  \frac{100}{4}

x = 1900

the total number of students is 1900

4) increase = 20%

new salary = 24000 rupees

let his original salary be = y

\frac{20}{100}  \times y = 24000 - y

0.2y = 24000 - y

0.2y + y = 24000

1.2y = 24000

y =  \frac{24000}{1.2}

y = 20000

his original salary is 20,000 rupees

7 0
3 years ago
Se tienen 16 maquinas cuyo rendimiento es del 90% y produce 4800 articulos en 6 dias trabajando 10horas diarias. Si se desea pro
cupoosta [38]

Answer:

5 máquinas.

Step-by-step explanation:

Sabemos que con 16 máquinas, cada una con un rendimiento del 90%, se producen 4800 artículos en 6 días trabajando 10 horas diarias.

Primero extraigamos toda la información útil de esto.

Sea R la velocidad con la que trabaja una máquina con un rendimiento del 100%.

Entonces nuestras máquinas van a trabajar a:

(90%/100%)*R = 0.9*R

16 máquinas juntas trabajaran en total a 16 veces esa cantidad, o:

16*0.9*R

Luego también sabemos que las máquinas trabajan 10 horas al día por 6 días, es decir, trabajan un total de:

6*10h = 60h

60 horas.

Entonces podemos plantear la ecuación:

(16*0.9*R)*60h = 4800 artículos.

Ahora podemos despejar el valor de R.

R = (4800 artículos)/(16*0.9*60 horas) = 5.556 artículos/hora

Ahora:

Se desea producir 1200 artículos.

En 8 días trabajando 9 horas al día, es decir en:

8*9h = 72 horas

Con N máquinas al 60%.

Cada máquina al 60% trabajara con una velocidad de:

0.6*R

N máquinas entonces trabajaran en conjunto a:

N*(0.6*R)

Con la información que se nos da, podemos plantear la ecuación:

N*(0.6*R)*72horas = 1200 artículos.

Queremos resolver esto para N, el número de máquinas, entonces aislamos N

N = (1200 artículos)/((0.6*R)*72horas)

Reemplazando el valor de R, que es 5.556 artículos/hora

N = (1200 artículos)/((0.6*5.556 artículos/hora)*72horas) = 5

Se necesitaran 5 máquinas.

5 0
3 years ago
You and your friend rent a canoe. The canoe costs 10 dollars per half hour plus 5 dollars per day for each life vest. Life vests
REY [17]
The greatest range....the range is ur y value, it will be the total cost...the x is gonna be the number of 1/2 hrs. And the 5 per life vest has to be multiplied by 2 because there is 2 people, making it 10
y = 10x + 10

the greatest range will be when u rent the canoe for the longest.
8 a.m to 6 p.m......thats 10 hrs....20 half hrs...so the greatest range is when u rent the canoe for 20 half hrs.

y = 10(20) + 10
y = 200 + 10
y = 210 <=== the greatest range
3 0
3 years ago
What is the additive inverse of t ? *
antiseptic1488 [7]

Answer:

-t

Step-by-step explanation:

Additive inverse of t:

t*-1 = -t

6 0
3 years ago
Read 2 more answers
Which of the following is a factor of 24x6 − 1029y3?
amid [387]

Answer:

The answer to your question is only the second and the third are factors.

Step-by-step explanation:

Find the factors of               24x⁶ − 1029y³

First find the prime factors of 24 and 1029

  24  2                1029 3

  12   2                  343 7                  Then 24 = 2³3

   6   2                    49  7                         1029 = 7³ 3

   3   3                       7  7

   1                             1

     x⁶ = (x²)³                  y³ = y³

Then

                                  2³3(x²)³  -  7³ 3  y³

Factor 3                    3[  2³(x²)³  -  7³ y³]

Factor                      3 [ (2x² - 7y)(4x⁴ + 14x²y + 49y²)]

Then

24

2x2 + 7y

4x4 + 14x2y + 49y2

All of the above

8 0
3 years ago
Read 2 more answers
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