All categories

3 years ago

What is the correct step to solve this equation?

Mathematics

2 answers:

anyanavicka [17]3 years ago

7 0

It’s A.
4-4=0
10-4=6
Check your work by putting the number in and see if it’s right
6+4=10

ehidna [41]3 years ago

6 0

Answer: C add 4 to both sides
I hope this helps you !

You might be interested in

Someone help please, i cant solve this one :|

andrey2020 [161]

Answer:

i think its B

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A large container holds 4.9 gallons of water. Use the following information to convert this amount of water to liters. Round you

Ivenika [448]

Answer:

the gallons must be convert to quarts. 4.9 gallons equals 20.6 quarts. 20.6 quarts divide by 1.057 liters equals 19.489 liters.

3 0

3 years ago

Please help me Algebra 1

Oduvanchick [21]

Answer:

a. $\sqrt{x^n}$ = $x^\frac{n}{2}$

b. $\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

Step-by-step explanation:

a) When n is even, then it is divisible by 2. Because of this, you can write:

$\sqrt{x^n} = (x^n)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{n}{2}$

b) When n is odd, then n - 1 is even. This would make it divisible by 2, and there would be a remainder of 1, so we can write:

$\sqrt{x^n} = (x^n^-^1^+^1) ^\frac{1}{2}$

$\sqrt{x^n} = (x^n^-^1$ × $x)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}$ × $x^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

8 0

2 years ago

Read 2 more answers

What is the slope-intercept equation of the line below?

Andru [333]

Answer:

y= -3x+4

I hope this helps <3 have an amazing and wonderful day <3

Step-by-step explanation:

3 0

2 years ago

Define fn : [0,1] --> R by the

sasho [114]

Answer:

The sequence of functions $\{x^{n}\}_{n\in \mathbb{N}}$ converges to the function

$f(x)=\begin{cases}0&0\leq x$ .

Step-by-step explanation:

The limit $\lim_{n\to \infty }c^{n}$ exists and converges to zero whenever $\lvert c \rvert$ . But, if $c=1$ the sequence $\{c^{n}\}$ is constant and all its terms are equal to $1$ , then converges to $1$ . Using this result, consider the sequence of functions $\{f_{n}\}$ defined on the interval $[0,1]$ by $f_{n}(x)=x^{n}$ . Then, for all $0\leq x$ we have that $\lim_{n\to \infty}x^{n}=0$ . Now, if $x=1$ , then $\lim_{n\to \infty }x^{n}=1$ . Therefore, the limit function of the sequence of functions is