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3 years ago

9

What is the correct step to solve this equation?

2 answers:

anyanavicka [17]3 years ago

7 0

It’s A.
4-4=0
10-4=6
Check your work by putting the number in and see if it’s right
6+4=10

ehidna [41]3 years ago

6 0

Answer: C add 4 to both sides
I hope this helps you !

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6 is 3% of what number?

Aleks04 [339]

<span>✡ Answer: 200 </span><span>✡

- - Solve:

✡ First we need to find the formula to solve:
$\frac{3}{100} * x=6$

✡ Now:
x is equal to: $\frac{100*6}{3}$

</span>
<span>✡Now we are going to multiply $100*2$ to get our answer.

- - 100*2=200 </span>

✡Hope this helps!<span>✡</span>

6 0

3 years ago

Read 2 more answers

Which of the following is the solution to the equation 4 / 5n = 20?

S_A_V [24]

N=25 because 20 divided by 4 is 5 which is 1/5 of n meaning 5x5 is 25

5 0

3 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

<em> </em> $\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$ <em></em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the definite integration</em>

<em> </em> $\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$ <em></em>

<em>we know that the trigonometric formula</em>

<em> sin²∝+cos²∝ = 1</em>

<em> cos²∝ = 1-sin²∝</em>

<u><em>step(ii):-</em></u>

<em>Now the integration</em>

<em> </em> $\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$ <em></em>

<em> = </em> $\int\limits^\pi _0 {cos\alpha } \, dx$ <em></em>

<em>Now, Integrating </em>

<em> </em> $= ( sin\alpha )_{0} ^{\pi }$ <em></em>

<em> = sin π - sin 0</em>

<em> = 0-0</em>

<em> = 0</em>

<u><em>Final answer:-</em></u>

<em> </em> $\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$ <em></em>

<em></em>

<em></em>

5 0

3 years ago

Which whole number is closest to 577.41 closest to?

Stella [2.4K]

578 bc 2 goes into 578 evenly

7 0

3 years ago

It is the one closest to the top plz Help

s344n2d4d5 [400]

Answer:

3.6 ft

Step-by-step explanation:

6 0

3 years ago