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Dafna1 [17]
3 years ago
15

How can shorter string produce more fundamental frequency in two string of different length?​

Physics
1 answer:
Nana76 [90]3 years ago
5 0

Answer:

Shorter string produces more frequency in two different strings because the equation for frequency is velocity/wavelength , this means that a shorter string creates a shorter wavelength which essentially increases the total frequency produced

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What is the distance between lines on a diffraction grating that produces a second-order maximum for 760-nm red light at an angl
Nataly [62]
The condition for maximum intensity is the same as that for a double slit. However, angular separation of the maxima is generally much greater because the slit spacing is so small for a diffraction grating. For a diffraction grating with lines/mm = lines/inch, the slit separation is d = micrometers = x10^ m.
8 0
2 years ago
Sunlight has its maximum intensity at a wavelength of 4.83 x 10'm; wha energy does this correspond to in e?
Lera25 [3.4K]

Answer:

E = 2,575 eV

Explanation:

For this exercise we will use the Planck equation and the relationship of the speed of light with the frequency and wavelength

     E = h f

     c = λ f

Where the Planck constant has a value of 6.63 10⁻³⁴ J s

Let's replace

    E = h c / λ

Let's calculate for wavelengths

    λ = 4.83 10-7 m     (blue)

    E = 6.63 10⁻³⁴ 3 10⁸ / 4.83 10⁻⁷

    E = 4.12 10-19 J

The transformation from J to eV is 1 eV = 1.6 10⁻¹⁹ J

    E = 4.12 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

    E = 2,575 eV

5 0
4 years ago
Calculate the Reynolds number for an oil gusher that shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter
Alenkasestr [34]

Answer:

Re=1992.24

Explanation:

Given:

vertical height of oil coming out of pipe, h=25\ m

diameter of pipe, d=0.1\ m

length of pipe, l=50\ m

density of oil, \rho = 900\ kg.m^{-3}

viscosity of oil, \mu=1\ Pa.s

Now, since the oil is being shot verically upwards it will have some initial velocity and will have zero final velocity at the top.

<u>Using the equation of motion:</u>

v^2=u^2-2gh

where:

v = final velocity

u = initial velocity

Putting the respective values:

0^2=u^2-2\times 9.8\times 25

u=22.136\ m.s^{-1}

<u>For Reynold's no. we have the relation as:</u>

Re=\frac{\rho.u.d}{\mu}

Re=\frac{900\times 22.136\times 0.1}{1}

Re=1992.24

6 0
3 years ago
PLEASE HELP I GIVE BRAINLIEST AND 15 POINTS
deff fn [24]
The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
10
60
​
= 6 Kg
Acceleration due to gravity on the moon is83%less than the acceleration due to gravity on earth(1.622m/s
2
).
F=ma
F=6.1.622=9.732 N
So a person weighting 60N on earth would approximately weight around 10Non the moon.
8 0
3 years ago
Wave length of sodium light is 5893A express in nanometre​
DaniilM [7]

Answer:

589.3 nm

Explanation:

The wavelength of a sodium light is 5893 A.

We need to find the wavelength in nm.

5893\ A=5893\times 10^{-10}\ m

Also, 1\ nm=10^{-9}\ m

5893\ A=5893\times 10^{-9}\times 10^{-1}\ m\\\\=5893\times 10^{-1}\ nm\\\\=589.3\ nm

So, the wavelength of sodium light is 589.3 nm.

8 0
3 years ago
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