Acceleration= velocity/time
1.1/2.7=0.41
The acceleration is .41 m/s^2
Answer:
I=
Explanation:
We are given that
Mass of rod=M
Length of rod=L
Mass of hoop=M
Radius of hoop=R
We have to find the moment of inertia I of the pendulum about pivot depicted at the left end of the slid rod.
Moment of inertia of rod about center of mass=
Moment of inertia of hoop about center of mass=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Moment of inertia of the pendulum about the pivot left end,I=
Answer:
77.88 lbm/ft³
Explanation:
Given,
Specific gravity, SG = 1.25
Density of water, ρ = 62.30 lbm/ft³
density of the fluid =
= S.G x ρ_{water}
= 62.30 x 1.25
= 77.88 lbm/ft³
Density of the fluid is equal to 77.88 lbm/ft³
In physics weight is the force exerted on a body by gravity so, the seller should have said it has a mass of 1 kg because mass is the amount of matter in an object.