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lakkis [162]
2 years ago
9

HELP PLEASE!!!!!!!

Physics
2 answers:
Roman55 [17]2 years ago
8 0

The silver substance is most likely a metal. Your answer is A.

Naily [24]2 years ago
7 0

Answer:

D or B

Explanation:

Hope this helps

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Fred has a very detailed model of the solar system where each planet is made out of granite rock. Since his little sister really
eimsori [14]
C or "Density" The granite rock has a much higher density than the Styrofoam. 
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3 years ago
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A radio has 100J of energy transferred by electricity. 20J are transferred by heating and 10J are transferred by sound. How many
seraphim [82]

Answer:

70 Joules

Explanation:

3 0
3 years ago
An aluminum wire is 5.87 m long and has a diameter of 6.07 mm.
antoniya [11.8K]

Answer: 5.72 x 10-3Ω

Explanation:

Hi, to answer this question, first we have to calculate the cross sectional area of the cable:

Diameter (D)=6.07 mm

Since: 1000mm = 1m

6.07mm/ 1000mm/m = 0.00607 meters

Area of a circle : π (d/2)^2

A = π (0.00607/2)^2= 0.000028937 m2

Resistance formula:

Resistance (R) = P(resistivity) L (length)÷A (cross sectional area )

Replacing with the values given:

R = (2.82x10-8 x 5.87) / 0.000028937

R = 5.72 x 10-3Ω

Feel free to ask for more if needed or if you did not understand something.

7 0
3 years ago
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!! THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THAN
timurjin [86]

Answer:

f_{o} = 391.67 Hz

Explanation:

The sound of lowest frequency which is produced by a vibrating sting is called its fundamental frequency (f_{o}).

The For a vibrating string, the fundamental frequency (f_{o}) can be determined by:

f_{o} = \frac{v}{2L}

Where v is the speed of waves of the string, and L is the length of the string.

L = 42.0 cm = 0.42 m

v = 329 m/s

f_{o} = \frac{329}{2*0.42}

   = \frac{329}{0.84}

f_{o} = 391.6667 Hz

The fundamental frequency of the string is 391.67 Hz.

3 0
2 years ago
A 500-N weight sits on the small piston of a hydraulic machine. The small piston has area 2.0 cm2. If the large piston has area
weqwewe [10]

Answer:

W₂= 10000 N

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area (A2) of the piston:

Pressure is defined as the force (F) applied per unit area (A)

P=F/A   (N/m²)

P1=P2

\frac{F_{1} }{A_{1} } = \frac{F_{2} }{A_{2} }

F_{2} = \frac{F_{1}*A_{2}  }{A_{1}}  Equation (1)

Data

W₁ = weight sits on the small piston

F₁ = W₁= 500 N

A₁ = 2.0 cm²

A₂ = 40 cm²

Calculation of the weight  (W₂) can the large piston support

We replace data in the equation (1)

F_{2} = \frac{(500)*(40) }{2}

F₂ = 10000 N

W₂= F₂= 10000 N

6 0
3 years ago
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