Equation C: a = 4b + 5 Equation D: a = 6b − 2 What value of a can be substituted into equation D to solve the system of equation
s? 4b + 5 6b − 2 4b 6b
2 answers:
Answer:
The correct answer is 4b + 5 ( A )
Step-by-step explanation:
Took the test and got it right trust me its A
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Answer:
The value of a that can substituted into equation D = 4b + 5
Step-by-step explanation:
Given that:
a = 4b + 5 ---- (equation c)
a = 6b - 2 ---- (equation d)
Replace the value of a = 4b + 5 into "a" in (equation d) to solve the system of equations.
So;
4b + 5 = 6b -2
5 + 2 = 6b -4b
7 = 2b
b = 7/2
b = 3.5
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