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NeTakaya
3 years ago
14

Ron finds 9 books at a bookstore that he would like to buy, but he can afford only 5 of them. In how many ways can he make his s

election? How many ways can he make his selection if he decides that one of the books is a must?
Mathematics
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

15,120 for the first question. 1,680 if one of the books is a must

Step-by-step explanation:

When Ron chooses his first book, he has 9 options. After that, when he chooses his second book, he only has 8 choices because he already picked one of them. By his third choice, he only has 7 choices and so on.

We can make an equation to represent this,

9 x 8 x 7 x 6 x 5

Multiplying all of that out gets you 15,120.

The second problem is even easier. Since one of the books is already chosen for him, he starts off only having 8 options. Since he is only choosing four books this time, we are only multiplying four numbers.

8 x 7 x 6 x 5

Multiplying all of that out tells you there are 1,680 ways he can make his selection in the second scenario.

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3 years ago
Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer a
soldi70 [24.7K]

Answer:

length of side of square = (4x - 5) inches

Step-by-step explanation:

We are given;

Area of square = 16x² – 40x + 25

Let's find the roots of this quadratic equation [-b ± √(b² - 4ac)]/2a

Thus;

x = [-(-40) ± √((-40)² - 4(16 × 25)]/(2×16)

x = [40 ± √(1600 - 1600)]/32

x = (40 ± 0)/32

x = 40/32

x = 5/4

Thus, the factors of the polynomial are;

(4x - 5)²

So,

Area = 16x² – 40x + 25 = (4x - 5)²

Since, the right hand side is (4x - 5)² and area of square is (length of side)², thus we can say that length of side of square is (4x - 5) inches

6 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y
katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are  (h  ±  a  ,  k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is  2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

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