The area of the rectangular floor in Tamara's room is 95 5/6 square

Mathematics

2 answers:

White raven [17]3 years ago

8 0

Area of rectangle is width × length
which means area of rectangular floor in Tamara's room = width of room × length of room
-> 95 ⅚ sq feet = 8 ⅓ feet × length of
->(95 + 5/6) sq feet = (8 + 1/3) feet × length of room
->575/6 sq feet = 25/3 feet × length of room
length of room = (575/6)/(25/3)
= 575 × 3/6 × 25)
= 23/2
= 11 ½ feet

marin [14]3 years ago

5 0

Area of the 346+99;$ djdjekdjdjj

You might be interested in

Write 7,380,000,000 in scientific notation. A. B. C. D.

elena-14-01-66 [18.8K]

7.38 x 10^9 is the correct answer. Hope this helps

7 0

3 years ago

Read 2 more answers

Which of the following statements are true?

Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is false.

B. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{x}$ is vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so the domain and the range of both functions are the same. This option is true.

C. The graph of the function $f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)}$ is translated 2 units to the right and vertically shrunk by a factor $\frac{1}{2}$ the graph of the function $f(x)=\sqrt[3]{x},$ so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of $\frac{1}{2}.$ . This option is true.

D. The function $f(x)=\dfrac{1}{2}\sqrt{x}$ has the domain and the range all non-negative real values. The function $f(x)=\sqrt[3]{x}$ has the domain and the range all real values. So this option is false.