Question

A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 12/20. The probability of the arrow landing on a section colored blue is 6/20. What is the probability of the arrow landing on a green-colored section? ​

Answer 1

Answer:

2/20

Step-by-step explanation:

12 + 6 is 18 so then your remaining would be 2 so your answer should be 2/20!

Answer 2

Answer:

$\frac{2}{20}$

Step-by-step explanation:

We have 3 sections.

1. $\frac{12}{20}$
2. $\frac{6}{20}$
3. $\frac{x}{20}$

Since we only have 3 sections, we can add red and blue, and subtract  $\frac{20}{20}$

$\frac{12}{20} + \frac{6}{20} = \frac{18}{20}$

Subtract:

$\frac{20}{20}-\frac{18}{20} = \frac{2}{20}$