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ale4655 [162]
2 years ago
14

Greg has 5 baseball bats that have lengths of: 3/4 yards, 2/3 yards, 1/2 yards, 7/8 yards, 1 1/8 yards. What is the difference i

n length between his longest and shortest bats?

Mathematics
1 answer:
max2010maxim [7]2 years ago
4 0

Answer:

1 1/8-4/8= 3/8

Step-by-step explanation:

Make sure they all have the same common denominator (24). Then pick out the smallest number and largest number,, and subtract.

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Can someone answer this?
sesenic [268]

C.. third one

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6 0
3 years ago
In a simple random sample of 14001400 young​ people, 9090​% had earned a high school diploma. Complete parts a through d below.
ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has ​increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

\hat p=0.90

(a)

The standard error for the estimate of the percentage of all young people who earned a high school​ diploma is given by:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the standard error value as follows:

SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

       =\sqrt{\frac{0.90(1-0.90)}{1400}}\\

       =0.008

Thus, the standard error for the estimate of the percentage of all young people who earned a high school​ diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

MOE=z_{\alpha/2}\times SE_{\hat p}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the margin of error as follows:

MOE=z_{\alpha/2}\times SE_{\hat p}

          =1.96\times 0.0080\\=0.01568\\\approx1.6\%

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has​ increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not​ increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has ​increased.

8 0
3 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
SVEN [57.7K]
(g-f)(x)=g(x)=f(x)

(g-f)(x)=6x-4+x^2

(g-f)(x)=x^2+6x-4  then:

(g-f)(3)=3^2+6*3-4

(g-f)(3)=9+18-4

(g-f)(x)=23
7 0
3 years ago
Help asap please need answer
Helga [31]

Answer:

is this on edulastic? if you have the option check answer put 12 and let me know if it was right please.

4 0
2 years ago
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What is the slope intercept equation of the line below?
valentina_108 [34]
The answer is letter D
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2 years ago
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