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3 years ago

Third time posting. Explain it too

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

5 0

Answer:

oooooooof

Step-by-step explanation:

maw [93]3 years ago

4 0

Answer:

D. x-5 / x+4

Step-by-step explanation:

(-3x³ +9x² +30x) / (-3x³ -18x² - 24x)

=-3x (x²-3x-10) / -3x(x²+6x+8)

=-3x(x+2)(x-5) / -3x(x+2)(x+4)

=x-5 / x+4

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Simplify each expression....remember you can

Vera_Pavlovna [14]

1. 14y
2. 8x
3. 2x + 8y
4. 8x + 2
5. 6x + 6
6. 8x + 4

4 0

3 years ago

Read 2 more answers

Please, I can really use some help. I have no idea how to solve this.

lions [1.4K]

A.
Use technology to plot the graph.
Here it is using wolframalpha.com.
http://www.wolframalpha.com/input/?i=y+%3D+-5;+y+%3D+3x+-+2+for+-2%3C%3Dx%3C%3D2

B.
The solution is where the graphs of the lines intersect. It is at point (-1, -5).

C.
y = -5
y = 3x - 2
-5 = 3x - 2
3x = -3
x = -1
The solution is (-1, -5) which is the same as with the graph.

8 0

3 years ago

Read 2 more answers

Can somebody please help me with this true or false algebra 1 question?

MakcuM [25]

I'll help.

The answer to your question is True!!

4 0

2 years ago

HELP ASSAPPP WITH THIS QUESTION

NeTakaya

From 11 A.M. to 2 P.M. because that is when the line is constantly straight

7 0

3 years ago

When individuals in a sample of 150 were asked whether or not they supported capital punishment, the following information was o

borishaifa [10]

Answer:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

Step-by-step explanation:

For this problem we have the following observed values:

Yes 40 No 60 No Opinion 50

And we want to test the following hypothesis:

Null hypothesis: All the opinions are uniformly distributed

Alternative hypothesis: Not All the opinions are uniformly distributed

And for this case the statistic would be given by:

$\chi^2 = \sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The expected values for all the categories is :

$E_i =\frac{150}{3}=50$

And then the statistic would be given by:

$\chi^2 = \frac{(40-50)^2}{50}+\frac{(60-50)^2}{50}+\frac{(50-50)^2}{50}=4$

And the best option would be:

b. 4

7 0

3 years ago