Ask question

Ask question

All categories

3 years ago

11

Which step is the first incorrect step in the solution shown below? Solve: 5(x + 2) = 6x + 12 Step 1: 5x + 2 = 6x + 12 Step 2: -

x + 2 = 12 Step 3: -X = 10 Step 4: x = -10 O A. Step 1 OB. Step 2 C. Step 3 D. Step 4

1 answer:

Natalija [7]3 years ago

4 0

Answer:

Step 1

Step-by-step explanation:

Correct solution step-by-step:

1. 5(x + 2) = 6x + 12

2. 5x + 10 = 6x + 12

3. 5x - 6x = 12 - 10

4. -x = 2

5. x = -2

You might be interested in

Pllzzz help I’ll mark brainliest

icang [17]

Answer:

26°

Step-by-step explanation:

AC=tan 64

BC=x=sec 64

Using sine rule

(Sin 64)/tan 64 = (sin BAC)/sec 64

Cos 64 = (sin BAC)(cos 64)

Sin BAC= 1

BAC=90

ACB+ 64+90=180

ACB= 26°

3 0

3 years ago

Read 2 more answers

g100num [7]

Answer:

A

Step-by-step explanation:

7 0

3 years ago

I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

6 0

3 years ago

Use the following function rule to find f(0).<br> f(x)= -9 (3)^x<br> f (0 ) =

AlladinOne [14]

Step-by-step explanation:

<u>Substitute f(0) into the function:</u>

$f(0) = - 9(3)^{0}$

<u>Include exponent:</u>

$f(0) = - 9(1)$

<u>Multiply:</u>

$f(0) = - 9$

7 0

2 years ago

What the answer tonthis question 10x=-4(2x-9)

mylen [45]

10x = 4(2x -9)

10x = 8x - 36

10x - 8x = -36 - 8x

2x = -36

2x ÷ 2 = -36 ÷ 2

x = -18

If you need a better explanation just as in the comments.

Happy to help! Please mark as BRAINLIEST! Thanks

7 0

3 years ago