Answer:
96
Step-by-step explanation:
8 × 9 × 8/2 × 3
8 × 9 × 8/6
576/6 = 96
Answer:
1. x = -7
2. y = -1
Step-by-step explanation:
1.
-3x - 5 = 16 add 5 to both sides
-3x = 21 divide -3 to both sides
x = -7
2.
-4(y-2) = 12 distribute -4
-4y + 8 = 12 subtract 8 from both sides
-4y = 4 divide -4 to both sides
y = -1
SECOND PAGE
1. x = 9
2. y = -3
In this case you the probabilities can be multiplied similarly to if you flipped a coin twice. .45 * .80 = .36
So to work this out we need to find the 4th root of each of those and pick the one that gives an integer.
A:
![\sqrt[4]{1.6*10^1^1} = 632.455...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E1%7D%20%3D%20632.455...)
This is a decimal therefore <em>not</em> an integer.
B:
![\sqrt[4]{1.6*10^1^2} =1124.682...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E2%7D%20%3D1124.682...)
Again a decimal, therefore <em>not </em>an integer.
C:
![\sqrt[4]{1.6*10^1^3} =2000](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E3%7D%20%3D2000)
This is a whole number, so it <em>is </em>an integer.
D:
![\sqrt[4]{1.6*10^1^4} =3556.558...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E4%7D%20%3D3556.558...)
Decimal, therefore <em>not </em>an integer
E:
![\sqrt[4]{1.6*10^1^5} =6324.555...](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1.6%2A10%5E1%5E5%7D%20%3D6324.555...)
Again a decimal, <em>not</em> an integer.
The only one that gives an integer when put to the 4th root is C, therefore:
could be A^4, as the 4th root of it is an integer.